CAIE P1 2019 June — Question 3 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2019
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind curve equation from derivative (extended problem with normals, stationary points, or further geometry)
DifficultyModerate -0.8 This is a straightforward two-part question requiring basic differentiation concepts. Part (i) applies the chain rule with given rates (dy/dt = dy/dx × dx/dt), and part (ii) is standard integration with a boundary condition to find the constant. Both are routine textbook exercises with no problem-solving insight required.
Spec1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates1.08b Integrate x^n: where n != -1 and sums

3 A curve is such that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = x ^ { 3 } - \frac { 4 } { x ^ { 2 } }\). The point \(P ( 2,9 )\) lies on the curve.
  1. A point moves on the curve in such a way that the \(x\)-coordinate is decreasing at a constant rate of 0.05 units per second. Find the rate of change of the \(y\)-coordinate when the point is at \(P\). [2]
  2. Find the equation of the curve.

Question 3(i):
AnswerMarks Guidance
AnswerMark Guidance
\(\frac{dy}{dt} = \frac{dy}{dx} \times \frac{dx}{dt} = 7 \times -0.05\)M1 Multiply numerical gradient at \(x = 2\) by \(\pm 0.05\)
\(-0.35\) (units/s) or Decreasing at a rate of \((+)\ 0.35\)A1 Ignore notation and omission of units
Question 3(ii):
AnswerMarks Guidance
AnswerMark Guidance
\((y) = \frac{x^4}{4} + \frac{4}{x}\ (+c)\) oeB1 Accept unsimplified
Uses \((2, 9)\) in an integral to find \(c\)M1 The power of at least one term increase by 1
\(c = 3\) or \((y =)\frac{x^4}{4} + \frac{4}{x} + 3\) oeA1 A0 if candidate continues to a final equation that is a straight line
## Question 3(i):

| Answer | Mark | Guidance |
|--------|------|----------|
| $\frac{dy}{dt} = \frac{dy}{dx} \times \frac{dx}{dt} = 7 \times -0.05$ | M1 | Multiply numerical gradient at $x = 2$ by $\pm 0.05$ |
| $-0.35$ (units/s) **or** Decreasing at a rate of $(+)\ 0.35$ | A1 | Ignore notation and omission of units |

## Question 3(ii):

| Answer | Mark | Guidance |
|--------|------|----------|
| $(y) = \frac{x^4}{4} + \frac{4}{x}\ (+c)$ oe | B1 | Accept unsimplified |
| Uses $(2, 9)$ in an integral to find $c$ | M1 | The power of at least one term increase by 1 |
| $c = 3$ **or** $(y =)\frac{x^4}{4} + \frac{4}{x} + 3$ oe | A1 | A0 if candidate continues to a final equation that is a straight line |
3 A curve is such that $\frac { \mathrm { d } y } { \mathrm {~d} x } = x ^ { 3 } - \frac { 4 } { x ^ { 2 } }$. The point $P ( 2,9 )$ lies on the curve.\\
(i) A point moves on the curve in such a way that the $x$-coordinate is decreasing at a constant rate of 0.05 units per second. Find the rate of change of the $y$-coordinate when the point is at $P$. [2]\\

(ii) Find the equation of the curve.\\

\hfill \mbox{\textit{CAIE P1 2019 Q3 [5]}}