CAIE S2 2017 June — Question 3 6 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2017
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConfidence intervals
TypeCalculate CI from summary stats
DifficultyStandard +0.8 Part (a) is routine confidence interval calculation. Part (b) requires deeper understanding: recognizing that P(CI entirely above μ) = 0.04 (half of the 8% in upper tail), then calculating 0.04³ for independence—this is non-standard and conceptually subtle. Part (c) tests sampling theory understanding. The combination of routine calculation with a genuinely tricky probability interpretation elevates this above average difficulty.
Spec5.05d Confidence intervals: using normal distribution

3
  1. The waiting time at a certain bus stop has variance 2.6 minutes \({ } ^ { 2 }\). For a random sample of 75 people, the mean waiting time was 7.1 minutes. Calculate a \(92 \%\) confidence interval for the population mean waiting time.
  2. A researcher used 3 random samples to calculate 3 independent \(92 \%\) confidence intervals. Find the probability that all 3 of these confidence intervals contain only values that are greater than the actual population mean.
  3. Another researcher surveyed the first 75 people who waited at a bus stop on a Monday morning. Give a reason why this sample is unsuitable for use in finding a confidence interval for the mean waiting time.

Question 3(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(7.1 \pm z \times \sqrt{\frac{2.6}{75}}\)M1 Expression of correct form must be \(z\) (note MR var \(= 2.6^2\) can score M1) seen
\(z = 1.751\)B1
\(6.77\) to \(7.43\) (3 sfs)A1 Must be an interval
Question 3(b):
AnswerMarks Guidance
AnswerMarks Guidance
\(0.04^3\)M1 Allow \(0.08^3\) for M1
\(= 0.000064\)A1
Question 3(c):
AnswerMarks Guidance
AnswerMarks Guidance
e.g. Particular day or time of dayB1 Allow "Not random"
## Question 3(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $7.1 \pm z \times \sqrt{\frac{2.6}{75}}$ | M1 | Expression of correct form must be $z$ (note MR var $= 2.6^2$ can score M1) seen |
| $z = 1.751$ | B1 | |
| $6.77$ to $7.43$ (3 sfs) | A1 | Must be an interval |

## Question 3(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $0.04^3$ | M1 | Allow $0.08^3$ for M1 |
| $= 0.000064$ | A1 | |

## Question 3(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| e.g. Particular day or time of day | B1 | Allow "Not random" |
3
\begin{enumerate}[label=(\alph*)]
\item The waiting time at a certain bus stop has variance 2.6 minutes ${ } ^ { 2 }$. For a random sample of 75 people, the mean waiting time was 7.1 minutes. Calculate a $92 \%$ confidence interval for the population mean waiting time.
\item A researcher used 3 random samples to calculate 3 independent $92 \%$ confidence intervals. Find the probability that all 3 of these confidence intervals contain only values that are greater than the actual population mean.
\item Another researcher surveyed the first 75 people who waited at a bus stop on a Monday morning. Give a reason why this sample is unsuitable for use in finding a confidence interval for the mean waiting time.
\end{enumerate}

\hfill \mbox{\textit{CAIE S2 2017 Q3 [6]}}