CAIE S1 2011 November — Question 2 6 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2011
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeCalculate variance/SD from coded sums
DifficultyModerate -0.8 This is a straightforward application of standard formulas for variance/SD from coded data. Students need to recall that Var(x) = E[(x-a)²] - [E(x-a)]² and apply algebraic manipulation to find Σx². The question requires routine substitution into well-practiced formulas with no conceptual challenges or problem-solving insight.
Spec2.02g Calculate mean and standard deviation

2 The values, \(x\), in a particular set of data are summarised by $$\Sigma ( x - 25 ) = 133 , \quad \Sigma ( x - 25 ) ^ { 2 } = 3762 .$$ The mean, \(\bar { x }\), is 28.325 .
  1. Find the standard deviation of \(x\).
  2. Find \(\Sigma x ^ { 2 }\).

Question 2:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(133/n + 25 = 28.325\)M1 Equation involving 133, 25 and 28.325
\(n = 40\)A1 Correct answer for \(n\)
\(3762/40 - 3.325^2 = 82.99\)M1 Using coded mean in variance formula
standard deviation \(= 9.11\)A1 [4] Correct answer
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(82.99 = \Sigma x^2/40 - 28.325^2\)M1 Using uncoded material in variance formula
\(\Sigma x^2 = (82.99 + 28.325^2) \times 40\)
\(= 35412\ (35400)\)A1 Correct answer
OR
\(\Sigma(x-25)^2 = \Sigma x^2 - 50\Sigma x + 40 \times 25^2\)M1 Expanding and substituting for \(\Sigma x\)
\(\Sigma x^2 = 3762 + 50 \times 1133 + 25000\)
\(= 35412\)A1 [2] Correct answer
## Question 2:

### Part (i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $133/n + 25 = 28.325$ | M1 | Equation involving 133, 25 and 28.325 |
| $n = 40$ | A1 | Correct answer for $n$ |
| $3762/40 - 3.325^2 = 82.99$ | M1 | Using coded mean in variance formula |
| standard deviation $= 9.11$ | A1 [4] | Correct answer |

### Part (ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $82.99 = \Sigma x^2/40 - 28.325^2$ | M1 | Using uncoded material in variance formula |
| $\Sigma x^2 = (82.99 + 28.325^2) \times 40$ | | |
| $= 35412\ (35400)$ | A1 | Correct answer |
| **OR** | | |
| $\Sigma(x-25)^2 = \Sigma x^2 - 50\Sigma x + 40 \times 25^2$ | M1 | Expanding and substituting for $\Sigma x$ |
| $\Sigma x^2 = 3762 + 50 \times 1133 + 25000$ | | |
| $= 35412$ | A1 [2] | Correct answer |

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2 The values, $x$, in a particular set of data are summarised by

$$\Sigma ( x - 25 ) = 133 , \quad \Sigma ( x - 25 ) ^ { 2 } = 3762 .$$

The mean, $\bar { x }$, is 28.325 .\\
(i) Find the standard deviation of $x$.\\
(ii) Find $\Sigma x ^ { 2 }$.

\hfill \mbox{\textit{CAIE S1 2011 Q2 [6]}}