CAIE S1 2005 November — Question 3 7 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2005
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPermutations & Arrangements
TypeArrangements with identical objects
DifficultyModerate -0.8 This is a straightforward permutations question requiring basic counting principles. Part (i) uses the standard formula for arrangements with identical objects (13!/(9!4!)), part (ii) treats grouped spaces as a single unit (10 arrangements), and part (iii) applies simple probability. All techniques are routine for S1 level with no novel problem-solving required.
Spec5.01a Permutations and combinations: evaluate probabilities5.01b Selection/arrangement: probability problems

3 A staff car park at a school has 13 parking spaces in a row. There are 9 cars to be parked.
  1. How many different arrangements are there for parking the 9 cars and leaving 4 empty spaces?
  2. How many different arrangements are there if the 4 empty spaces are next to each other?
  3. If the parking is random, find the probability that there will not be 4 empty spaces next to each other.

(i) \(_13P_9 = 259,459,200\) or \(259,000,000\)
AnswerMarks Guidance
For using a permutation involving 13M1
For correct answerA1 2 marks
(ii) \(10!\) or \(_10p = 3628800\)
AnswerMarks Guidance
For using a 10M1
For using a 9!M1
For correct answerA1 3 marks
(iii) \(1 - (ii) / (i) = 0.986\)
AnswerMarks Guidance
For a subtraction of a suitable prob \(< 1\), from 1M1
For correct answer, ft on their (i) and (ii)A1 ft 2 marks
**(i)** $_13P_9 = 259,459,200$ or $259,000,000$

| For using a permutation involving 13 | M1
| For correct answer | A1 | 2 marks

**(ii)** $10!$ or $_10p = 3628800$

| For using a 10 | M1
| For using a 9! | M1
| For correct answer | A1 | 3 marks

**(iii)** $1 - (ii) / (i) = 0.986$

| For a subtraction of a suitable prob $< 1$, from 1 | M1
| For correct answer, ft on their (i) and (ii) | A1 ft | 2 marks
3 A staff car park at a school has 13 parking spaces in a row. There are 9 cars to be parked.\\
(i) How many different arrangements are there for parking the 9 cars and leaving 4 empty spaces?\\
(ii) How many different arrangements are there if the 4 empty spaces are next to each other?\\
(iii) If the parking is random, find the probability that there will not be 4 empty spaces next to each other.

\hfill \mbox{\textit{CAIE S1 2005 Q3 [7]}}