CAIE S1 2010 June — Question 3 5 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2010
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Distribution
TypeMultiple independent binomial calculations
DifficultyModerate -0.3 This question involves straightforward applications of binomial probability formulas and basic probability laws. Part (i) is a direct binomial calculation, part (ii) uses the law of total probability with given conditional probabilities, and part (iii) applies the variance formula for a binomial distribution. All three parts are routine textbook exercises requiring recall and standard methods rather than problem-solving or insight.
Spec2.03d Calculate conditional probability: from first principles5.02d Binomial: mean np and variance np(1-p)

3 Christa takes her dog for a walk every day. The probability that they go to the park on any day is 0.6 . If they go to the park there is a probability of 0.35 that the dog will bark. If they do not go to the park there is a probability of 0.75 that the dog will bark.
  1. Find the probability that they go to the park on more than 5 of the next 7 days.
  2. Find the probability that the dog barks on any particular day.
  3. Find the variance of the number of times they go to the park in 30 days.

AnswerMarks Guidance
(i) \(P(> 5) = ^7C_6(0.6)^6(0.4) + (0.6)^7 = 0.1306 + 0.02799 = 0.159\)M1 Summing 2 or 3 binomial probs of the form \(^nC_r(0.6)^r(0.4)^{n-r}\)
A1Correct answer
(ii) \(P(\text{bark}) = P(\text{park, bark}) + P(\text{not park, bark}) = 0.6 \times 0.35 + 0.4 \times 0.75 = 0.51\)M1 Summing two appropriate 2-factor probabilities
A1Correct answer
(iii) Variance (number of times) = 7.2B1 Correct final answer
**(i)** $P(> 5) = ^7C_6(0.6)^6(0.4) + (0.6)^7 = 0.1306 + 0.02799 = 0.159$ | M1 | Summing 2 or 3 binomial probs of the form $^nC_r(0.6)^r(0.4)^{n-r}$ |
| A1 | Correct answer |

**(ii)** $P(\text{bark}) = P(\text{park, bark}) + P(\text{not park, bark}) = 0.6 \times 0.35 + 0.4 \times 0.75 = 0.51$ | M1 | Summing two appropriate 2-factor probabilities |
| A1 | Correct answer |

**(iii)** Variance (number of times) = 7.2 | B1 | Correct final answer |

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3 Christa takes her dog for a walk every day. The probability that they go to the park on any day is 0.6 . If they go to the park there is a probability of 0.35 that the dog will bark. If they do not go to the park there is a probability of 0.75 that the dog will bark.\\
(i) Find the probability that they go to the park on more than 5 of the next 7 days.\\
(ii) Find the probability that the dog barks on any particular day.\\
(iii) Find the variance of the number of times they go to the park in 30 days.

\hfill \mbox{\textit{CAIE S1 2010 Q3 [5]}}