CAIE S1 2010 June — Question 1 4 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2010
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Probability Distributions
TypeTwo unknowns from sum and expectation
DifficultyModerate -0.8 This is a standard two-equation, two-unknown problem requiring only routine application of probability axioms (sum = 1) and expectation formula. The arithmetic is straightforward with no conceptual challenges, making it easier than average but not trivial since it requires setting up and solving simultaneous equations.
Spec5.02a Discrete probability distributions: general5.02b Expectation and variance: discrete random variables

1 The probability distribution of the discrete random variable \(X\) is shown in the table below.
\(x\)- 3- 104
\(\mathrm { P } ( X = x )\)\(a\)\(b\)0.150.4
Given that \(\mathrm { E } ( X ) = 0.75\), find the values of \(a\) and \(b\).

AnswerMarks Guidance
\(a + b = 0.45\) and \(-3a - b + 1.6 = 0.75\) giving \(a = 0.2\) and \(b = 0.25\)B1, M1, A1, A1 Correct sum probs = 1 o.e.; Attempt at \(\Sigma p = 0.75\); Correct \(a\); Correct \(b\)
$a + b = 0.45$ and $-3a - b + 1.6 = 0.75$ giving $a = 0.2$ and $b = 0.25$ | B1, M1, A1, A1 | Correct sum probs = 1 o.e.; Attempt at $\Sigma p = 0.75$; Correct $a$; Correct $b$ | **Total: [4]**

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1 The probability distribution of the discrete random variable $X$ is shown in the table below.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | }
\hline
$x$ & - 3 & - 1 & 0 & 4 \\
\hline
$\mathrm { P } ( X = x )$ & $a$ & $b$ & 0.15 & 0.4 \\
\hline
\end{tabular}
\end{center}

Given that $\mathrm { E } ( X ) = 0.75$, find the values of $a$ and $b$.

\hfill \mbox{\textit{CAIE S1 2010 Q1 [4]}}