## Question 7(a):

Includes all data | B1 | Reference to *either* including all/raw data or further statistical processes are possible that cannot be found using data from box-and-whisker, e.g. frequency, mean, mode or standard deviation **not** only median, IQR, range or spread which can be found from both

**Total: 1 mark**

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## Question 7(b):

Back-to-back stem-and-leaf diagram: | B1 | Correct stem can be upside down, ignore extra values

Amazons leaves correct, in order right to left, lined up vertically | B1 | Correct Amazons labelled on left, leaves in order from right to left and lined up vertically (less than halfway to next column), no commas or other punctuation

Giants leaves correct, in order, lined up vertically | B1 | Correct Giants labelled on same diagram, leaves in order and lined up vertically, no commas or other punctuation

Key: $1|18|2$ means 181 cm for Amazons and 182 cm for Giants | B1 | Correct single key, both teams identified and 'cm' stated at least once; SC for 2 separate diagrams, award SCB1 if both keys meet criteria (Max B1, B0, B0, B1)

**Total: 4 marks**

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## Question 7(c):

$[\text{UQ} = 202 \text{ cm},\ \text{LQ} = 182 \text{ cm}]$ | M1 | $201 \leq \text{UQ} \leq 205 - 181 \leq \text{LQ} \leq 184$

$[\text{IQR} =]\ 202 - 182 = 20 \text{ (cm)}$ | A1 | WWW

**Total: 2 marks**

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## Question 7(d):

$[\Sigma_{11} = 2132,\quad \Sigma_{15} = 191.2 \times 15 = 2868]$ | B1 | Both $\Sigma_{11}$ and $\Sigma_{15}$ found, accept unevaluated

$\textit{their } 2868 = \textit{their } 2132 + (180 + 185 + 190) + h$ | M1 | Forming an equation for height using *their* $\Sigma_{11}$ and $\Sigma_{15}$

$181 \text{ (cm)}$ | A1 |

**Alternative method:**

$[\Sigma_{15} = 2687 + h],\quad \dfrac{\Sigma_{15}}{15} = 191.2$ | B1 | $\Sigma_{15}$ found using raw data method and statement on calculating new mean, accept unevaluated

$\dfrac{\textit{their } 2687 + h}{15} = 191.2$ | M1 | Forming an equation using *their* $\Sigma_{15}$ expressions

$181 \text{ (cm)}$ | A1 |

**Total: 3 marks**