CAIE S1 2020 June — Question 6 10 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2020
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMeasures of Location and Spread
TypeConstruct back-to-back stem-and-leaf from raw data
DifficultyEasy -1.3 This is a straightforward data handling question requiring basic statistical skills: constructing a stem-and-leaf diagram from ordered data, finding median and IQR from 11 values (simple position formulas), and using the mean formula to find a missing value. All parts are routine recall and calculation with no problem-solving or conceptual challenge.
Spec2.02a Interpret single variable data: tables and diagrams2.02f Measures of average and spread2.02g Calculate mean and standard deviation

6 The annual salaries, in thousands of dollars, for 11 employees at each of two companies \(A\) and \(B\) are shown below.
Company \(A\)3032354141424749525364
Company \(B\)2647305241383542493142
  1. Represent the data by drawing a back-to-back stem-and-leaf diagram with company \(A\) on the left-hand side of the diagram.
  2. Find the median and the interquartile range of the salaries of the employees in company \(A\). [3]
    A new employee joins company \(B\). The mean salary of the 12 employees is now \(\\) 38500$.
  3. Find the salary of the new employee.

Question 6:
Part (a):
AnswerMarks Guidance
AnswerMark Guidance
Correct stemB1 KEY: \(1\
Correct A on LHSB1
Correct B on same diagramB1
Correct key for their diagram, both companies identified and correct unitsB1
Part (b):
AnswerMarks Guidance
AnswerMark Guidance
Median \(= [\\)]42\,000$B1
\(LQ = [\\)]35\,000\(; \)UQ = [\\(]52\,000\)B1
\(IQR = [\\)]17\,000\(B1 FT FT if \)49000 \leq UQ \leq 53000 - 32000 \leq LQ \leq 41000$
Part (c):
AnswerMarks Guidance
AnswerMark Guidance
Sum of given 11 numbers is \(433\,000\)M1
Sum of 12 numbers including new \(= 38\,500 \times 12 = 462\,000\)M1
Difference = new salary \(= [\\)]29\,000$A1
## Question 6:

### Part (a):
| Answer | Mark | Guidance |
|--------|------|----------|
| Correct stem | B1 | KEY: $1\|4\|2$ means \$41 000 for A and \$42 000 for B |
| Correct A on LHS | B1 | |
| Correct B on same diagram | B1 | |
| Correct key for their diagram, both companies identified and correct units | B1 | |

### Part (b):
| Answer | Mark | Guidance |
|--------|------|----------|
| Median $= [\$]42\,000$ | B1 | |
| $LQ = [\$]35\,000$; $UQ = [\$]52\,000$ | B1 | |
| $IQR = [\$]17\,000$ | B1 FT | FT if $49000 \leq UQ \leq 53000 - 32000 \leq LQ \leq 41000$ |

### Part (c):
| Answer | Mark | Guidance |
|--------|------|----------|
| Sum of given 11 numbers is $433\,000$ | M1 | |
| Sum of 12 numbers including new $= 38\,500 \times 12 = 462\,000$ | M1 | |
| Difference = new salary $= [\$]29\,000$ | A1 | |

---
6 The annual salaries, in thousands of dollars, for 11 employees at each of two companies $A$ and $B$ are shown below.

\begin{center}
\begin{tabular}{ | l | l | l | l | l | l | l | l | l | l | l | l | }
\hline
Company $A$ & 30 & 32 & 35 & 41 & 41 & 42 & 47 & 49 & 52 & 53 & 64 \\
\hline
Company $B$ & 26 & 47 & 30 & 52 & 41 & 38 & 35 & 42 & 49 & 31 & 42 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Represent the data by drawing a back-to-back stem-and-leaf diagram with company $A$ on the left-hand side of the diagram.
\item Find the median and the interquartile range of the salaries of the employees in company $A$. [3]\\

A new employee joins company $B$. The mean salary of the 12 employees is now $\$ 38500$.
\item Find the salary of the new employee.
\end{enumerate}

\hfill \mbox{\textit{CAIE S1 2020 Q6 [10]}}