CAIE M2 2016 November — Question 1 3 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2016
SessionNovember
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeHorizontal projection from height
DifficultyModerate -0.8 This is a straightforward projectile motion problem requiring only basic SUVAT equations and simple trigonometry. Students need to recognize that tan(30°) = vertical displacement / horizontal displacement, use s = ut + ½at² for vertical motion, and s = vt for horizontal motion. The calculation is routine with no conceptual challenges beyond standard M1/M2 content.
Spec3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model

1 A stone \(S\) is thrown horizontally from the top \(T\) of a high tower. At the instant 1.6 s after \(S\) is thrown, the line \(S T\) makes an angle of \(30 ^ { \circ }\) below the horizontal. Find the speed with which \(S\) is thrown. [3]

Question 1:
AnswerMarks Guidance
Working/AnswerMark Guidance
\(Y = g(1.6)^2/2\)B1 12.8 m
\(12.8/(1.6V) = \tan 30\)M1 \(1.6V = X = 22.17\) m
\(V = 13.9 \text{ ms}^{-1}\)A1
[3]
## Question 1:

| Working/Answer | Mark | Guidance |
|---|---|---|
| $Y = g(1.6)^2/2$ | B1 | 12.8 m |
| $12.8/(1.6V) = \tan 30$ | M1 | $1.6V = X = 22.17$ m |
| $V = 13.9 \text{ ms}^{-1}$ | A1 | |
| | [3] | |

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1 A stone $S$ is thrown horizontally from the top $T$ of a high tower. At the instant 1.6 s after $S$ is thrown, the line $S T$ makes an angle of $30 ^ { \circ }$ below the horizontal. Find the speed with which $S$ is thrown. [3]

\hfill \mbox{\textit{CAIE M2 2016 Q1 [3]}}