CAIE M2 2012 November — Question 1 6 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2012
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeLamina hinged at point with string support
DifficultyStandard +0.8 This is a multi-step moments problem requiring: (1) finding the combined center of mass using the formula for semicircular lamina/arc centers of mass (4r/3π and 2r/π), (2) taking moments about the hinge with a tilted geometry (30° angle complicates perpendicular distances), and (3) resolving the horizontal force and weights. The geometric setup and angle work elevate this above routine moments questions, but it's still a standard M2-level problem with clear structure.
Spec3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force6.04b Find centre of mass: using symmetry6.04c Composite bodies: centre of mass

1 \includegraphics[max width=\textwidth, alt={}, center]{e30ba526-db21-4904-96dc-c12a1f67c81a-2_426_531_258_808} A circular object is formed from a uniform semicircular lamina of weight 12 N and a uniform semicircular arc of weight 8 N . The lamina and the arc both have centre \(O\) and radius 0.6 m and are joined at the ends of their common diameter \(A B\). The object is freely pivoted to a fixed point at \(A\) with \(A B\) inclined at \(30 ^ { \circ }\) to the vertical. The object is in equilibrium acted on by a horizontal force of magnitude \(F\) N applied at the lowest point of the object, and acting in the plane of the object (see diagram).
  1. Show that the centre of mass of the object is at \(O\).
  2. Calculate \(F\).

AnswerMarks Guidance
(i)\(PE \text{ loss} = 0.8g \times (2.5 - 1.8) = 5.6J\) B1
Work done is 5.6 JB1 2 marks total
(ii)For using \(KE \text{ gain} = PE \text{ loss} - WD\) against resistance M1
\(\frac{1}{2} \times 0.8v^2 = 0.8g \times 2.5 - 0.6 \times 5.6\)A1ft
Speed at \(B\) is 6.45 ms\(^{-1}\)A1 3 marks total
(i) | $PE \text{ loss} = 0.8g \times (2.5 - 1.8) = 5.6J$ | B1 | |
| Work done is 5.6 J | B1 | 2 marks total |

(ii) | For using $KE \text{ gain} = PE \text{ loss} - WD$ against resistance | M1 | |
| $\frac{1}{2} \times 0.8v^2 = 0.8g \times 2.5 - 0.6 \times 5.6$ | A1ft | |
| Speed at $B$ is 6.45 ms$^{-1}$ | A1 | 3 marks total |

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\includegraphics[max width=\textwidth, alt={}, center]{e30ba526-db21-4904-96dc-c12a1f67c81a-2_426_531_258_808}

A circular object is formed from a uniform semicircular lamina of weight 12 N and a uniform semicircular arc of weight 8 N . The lamina and the arc both have centre $O$ and radius 0.6 m and are joined at the ends of their common diameter $A B$. The object is freely pivoted to a fixed point at $A$ with $A B$ inclined at $30 ^ { \circ }$ to the vertical. The object is in equilibrium acted on by a horizontal force of magnitude $F$ N applied at the lowest point of the object, and acting in the plane of the object (see diagram).\\
(i) Show that the centre of mass of the object is at $O$.\\
(ii) Calculate $F$.

\hfill \mbox{\textit{CAIE M2 2012 Q1 [6]}}