CAIE M2 2010 November — Question 1 3 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2010
SessionNovember
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypeRotating disc with friction
DifficultyModerate -0.8 This is a straightforward application of circular motion formula F = mω²r with all values directly given. Requires only substitution into a standard formula with no problem-solving, making it easier than average but not trivial since students must recognize the setup and recall the correct formula.
Spec6.05b Circular motion: v=r*omega and a=v^2/r

1 A horizontal circular disc rotates with constant angular speed \(9 \mathrm { rad } \mathrm { s } ^ { - 1 }\) about its centre \(O\). A particle of mass 0.05 kg is placed on the disc at a distance 0.4 m from \(O\). The particle moves with the disc and no sliding takes place. Calculate the magnitude of the resultant force exerted on the particle by the disc.

Question 1:
AnswerMarks Guidance
Working/AnswerMark Guidance
\(0.05 \times 9^2 \times 0.4 = H\)M1
\(H = 1.62\) NA1
\(R = 1.70\) NA1 [3] \(\sqrt{1.62^2 + 0.5^2}\)
## Question 1:

| Working/Answer | Mark | Guidance |
|---|---|---|
| $0.05 \times 9^2 \times 0.4 = H$ | M1 | |
| $H = 1.62$ N | A1 | |
| $R = 1.70$ N | A1 [3] | $\sqrt{1.62^2 + 0.5^2}$ |

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1 A horizontal circular disc rotates with constant angular speed $9 \mathrm { rad } \mathrm { s } ^ { - 1 }$ about its centre $O$. A particle of mass 0.05 kg is placed on the disc at a distance 0.4 m from $O$. The particle moves with the disc and no sliding takes place. Calculate the magnitude of the resultant force exerted on the particle by the disc.

\hfill \mbox{\textit{CAIE M2 2010 Q1 [3]}}