CAIE M2 2007 November — Question 5 7 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2007
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHooke's law and elastic energy
TypeWork-energy with multiple stages
DifficultyChallenging +1.2 This is a multi-part energy conservation problem with elastic strings requiring careful tracking of when each string is taut/slack and applying Hooke's law with energy methods. While it involves several steps and requires understanding of elastic potential energy in two strings, the approach is methodical and follows standard M2 techniques without requiring novel insight—moderately above average difficulty.
Spec6.02e Calculate KE and PE: using formulae6.02h Elastic PE: 1/2 k x^26.02i Conservation of energy: mechanical energy principle

5 Each of two light elastic strings, \(S _ { 1 }\) and \(S _ { 2 }\), has modulus of elasticity 16 N . The string \(S _ { 1 }\) has natural length 0.4 m and the string \(S _ { 2 }\) has natural length 0.5 m . One end of \(S _ { 1 }\) is attached to a fixed point \(A\) of a smooth horizontal table and the other end is attached to a particle \(P\) of mass 0.5 kg . One end of \(S _ { 2 }\) is attached to a fixed point \(B\) of the table and the other end is attached to \(P\). The distance \(A B\) is 1.5 m . The particle \(P\) is held at \(A\) and then released from rest.
  1. Find the speed of \(P\) at the instant that \(S _ { 2 }\) becomes slack.
  2. Find the greatest distance of \(P\) from \(A\) in the subsequent motion.

Question 5:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
M1For using \(EE = \frac{\lambda x^2}{2L}\)
M1For using \(EE_{S2}(\text{initial}) = \frac{1}{2}mv^2 + EE_{S1}\) (S2 just slack)
\(\frac{1}{2}(16 \times 1^2/0.5) = \frac{1}{2}(0.5)v^2 + \frac{1}{2}(16 \times 0.6^2/0.4)\)A1
Speed is \(5.93 \text{ ms}^{-1}\)A1 [4 marks]
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
M1For using \(EE_{S2}(\text{initial}) = EE_{S1}\)
\(\frac{1}{2}(16 \times 1^2/0.5) = \frac{1}{2}(16 \times x^2/0.4)\), \((x = 0.894)\)A1
Distance is 1.29mA1 [3 marks] [Total: 7]
## Question 5:

### Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| | M1 | For using $EE = \frac{\lambda x^2}{2L}$ |
| | M1 | For using $EE_{S2}(\text{initial}) = \frac{1}{2}mv^2 + EE_{S1}$ (S2 just slack) |
| $\frac{1}{2}(16 \times 1^2/0.5) = \frac{1}{2}(0.5)v^2 + \frac{1}{2}(16 \times 0.6^2/0.4)$ | A1 | |
| Speed is $5.93 \text{ ms}^{-1}$ | A1 | **[4 marks]** |

### Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| | M1 | For using $EE_{S2}(\text{initial}) = EE_{S1}$ |
| $\frac{1}{2}(16 \times 1^2/0.5) = \frac{1}{2}(16 \times x^2/0.4)$, $(x = 0.894)$ | A1 | |
| Distance is 1.29m | A1 | **[3 marks]** **[Total: 7]** |

---
5 Each of two light elastic strings, $S _ { 1 }$ and $S _ { 2 }$, has modulus of elasticity 16 N . The string $S _ { 1 }$ has natural length 0.4 m and the string $S _ { 2 }$ has natural length 0.5 m . One end of $S _ { 1 }$ is attached to a fixed point $A$ of a smooth horizontal table and the other end is attached to a particle $P$ of mass 0.5 kg . One end of $S _ { 2 }$ is attached to a fixed point $B$ of the table and the other end is attached to $P$. The distance $A B$ is 1.5 m . The particle $P$ is held at $A$ and then released from rest.\\
(i) Find the speed of $P$ at the instant that $S _ { 2 }$ becomes slack.\\
(ii) Find the greatest distance of $P$ from $A$ in the subsequent motion.

\hfill \mbox{\textit{CAIE M2 2007 Q5 [7]}}