CAIE M2 2019 March — Question 4 6 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2019
SessionMarch
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypeElastic string – conical pendulum (string inclined to vertical)
DifficultyStandard +0.3 This is a standard circular motion problem with elastic string requiring resolution of forces (tension, weight) and application of Hooke's law and centripetal force formula. It involves multiple steps but uses routine M2 techniques without requiring novel insight—slightly easier than average due to straightforward geometry and given angle.
Spec6.02g Hooke's law: T = k*x or T = lambda*x/l6.05c Horizontal circles: conical pendulum, banked tracks

4 \includegraphics[max width=\textwidth, alt={}, center]{b8e52188-f9a6-46fc-90bf-97965c6dd324-07_337_526_262_726} \includegraphics[max width=\textwidth, alt={}, center]{b8e52188-f9a6-46fc-90bf-97965c6dd324-07_111_116_486_1308} A particle \(P\) of mass 0.3 kg is attached to a fixed point \(A\) by a light elastic string of natural length 0.8 m and modulus of elasticity 16 N . The particle \(P\) moves in a horizontal circle which has centre \(O\). It is given that \(A O\) is vertical and that angle \(O A P\) is \(60 ^ { \circ }\) (see diagram). Calculate the speed of \(P\). [6]

Question 4:
AnswerMarks Guidance
AnswerMarks Guidance
\(T\cos 60 = 0.3g\)M1 Resolve vertically
\(T = 6\text{ N}\)A1
\(T = \frac{16e}{0.8} (= 6)\) leads to \(e = 0.3\)M1 Use \(T = \frac{\lambda x}{L}\)
\(r = (0.8 + 0.3)\sin 60 (= 1.1\sin 60)\)A1
\(T\sin 60 = \frac{0.3v^2}{1.1\sin 60}\)M1 Use N2L horizontally
\(v = 4.06 \text{ m s}^{-1}\)A1
6
## Question 4:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $T\cos 60 = 0.3g$ | M1 | Resolve vertically |
| $T = 6\text{ N}$ | A1 | |
| $T = \frac{16e}{0.8} (= 6)$ leads to $e = 0.3$ | M1 | Use $T = \frac{\lambda x}{L}$ |
| $r = (0.8 + 0.3)\sin 60 (= 1.1\sin 60)$ | A1 | |
| $T\sin 60 = \frac{0.3v^2}{1.1\sin 60}$ | M1 | Use N2L horizontally |
| $v = 4.06 \text{ m s}^{-1}$ | A1 | |
| | **6** | |
4\\
\includegraphics[max width=\textwidth, alt={}, center]{b8e52188-f9a6-46fc-90bf-97965c6dd324-07_337_526_262_726}\\
\includegraphics[max width=\textwidth, alt={}, center]{b8e52188-f9a6-46fc-90bf-97965c6dd324-07_111_116_486_1308}

A particle $P$ of mass 0.3 kg is attached to a fixed point $A$ by a light elastic string of natural length 0.8 m and modulus of elasticity 16 N . The particle $P$ moves in a horizontal circle which has centre $O$. It is given that $A O$ is vertical and that angle $O A P$ is $60 ^ { \circ }$ (see diagram). Calculate the speed of $P$. [6]\\

\hfill \mbox{\textit{CAIE M2 2019 Q4 [6]}}