CAIE P1 2014 June — Question 4 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2014
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeDerive equation from area/geometry
DifficultyStandard +0.3 This is a standard sector geometry problem requiring formula recall (area of sector = ½r²θ, area of triangle = ½r²sinθ) and basic algebraic manipulation. Part (i) involves setting up an equation from equal areas, leading to a simple rearrangement. Part (ii) is straightforward application of arc length and chord length formulas. Both parts are routine applications of AS-level circle geometry with no novel problem-solving required, making it slightly easier than average.
Spec1.05c Area of triangle: using 1/2 ab sin(C)1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

4 \includegraphics[max width=\textwidth, alt={}, center]{1a4ddaa9-1ec2-4138-bfcb-a482fe6c942f-2_358_618_1082_762} The diagram shows a sector of a circle with radius \(r \mathrm {~cm}\) and centre \(O\). The chord \(A B\) divides the sector into a triangle \(A O B\) and a segment \(A X B\). Angle \(A O B\) is \(\theta\) radians.
  1. In the case where the areas of the triangle \(A O B\) and the segment \(A X B\) are equal, find the value of the constant \(p\) for which \(\theta = p \sin \theta\).
  2. In the case where \(r = 8\) and \(\theta = 2.4\), find the perimeter of the segment \(A X B\).

AnswerMarks Guidance
(i) \(\frac{1}{2}r^2\theta = \frac{1}{2}r^2\theta - \frac{1}{2}r^2\sin\theta\) → \(2\sin\theta = \theta\) → \(p = 2.\)B1 B1 [2] Correct equation. All ok – answer given.
(ii) Chord length = \(8\sin1.2 \times 2\) (14.9) (or from cosine rule) Arc length = 2.4 × 8 (19.2) Perimeter = sum of these = 34.1M1 B1 A1 [3] Needs ×2. Any method ok. co
**(i)** $\frac{1}{2}r^2\theta = \frac{1}{2}r^2\theta - \frac{1}{2}r^2\sin\theta$ → $2\sin\theta = \theta$ → $p = 2.$ | B1 B1 [2] | Correct equation. All ok – answer given.

**(ii)** Chord length = $8\sin1.2 \times 2$ (14.9) (or from cosine rule) Arc length = 2.4 × 8 (19.2) Perimeter = sum of these = 34.1 | M1 B1 A1 [3] | Needs ×2. Any method ok. co
4\\
\includegraphics[max width=\textwidth, alt={}, center]{1a4ddaa9-1ec2-4138-bfcb-a482fe6c942f-2_358_618_1082_762}

The diagram shows a sector of a circle with radius $r \mathrm {~cm}$ and centre $O$. The chord $A B$ divides the sector into a triangle $A O B$ and a segment $A X B$. Angle $A O B$ is $\theta$ radians.\\
(i) In the case where the areas of the triangle $A O B$ and the segment $A X B$ are equal, find the value of the constant $p$ for which $\theta = p \sin \theta$.\\
(ii) In the case where $r = 8$ and $\theta = 2.4$, find the perimeter of the segment $A X B$.

\hfill \mbox{\textit{CAIE P1 2014 Q4 [5]}}