CAIE M2 2013 June — Question 4 6 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2013
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeBasic trajectory calculations
DifficultyModerate -0.8 This is a straightforward projectile motion question requiring standard SUVAT equations applied to vertical and horizontal components. All three parts follow directly from basic formulas with given angle, time of flight, and g=10 m/s². No problem-solving insight needed—pure routine calculation.
Spec3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model

4 A ball \(B\) is projected from a point \(O\) on horizontal ground at an angle of \(40 ^ { \circ }\) above the horizontal. \(B\) hits the ground 1.8 s after the instant of projection. Calculate
  1. the speed of projection of \(B\),
  2. the greatest height of \(B\),
  3. the distance from \(O\) of the point at which \(B\) hits the ground.

Question 4:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(V\sin40 - (1.8/2)g = 0\)M1 Or \(0 = (V\sin40)\times1.8 - g\times1.8^2/2\)
\(V = 14(.0)\) ms\(^{-1}\)A1 [2]
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\((14\sin40)^2 = 2gh\)M1 Or \(h = (V\sin40)\times0.9 - g\times0.9^2/2\)
\(h = 4.05\) mA1 [2]
Part (iii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(d = (14\cos40)\times1.8\)M1 Or \(d = V^2\sin80/g\)
\(d = 19.3\) mA1 [2] [6]
## Question 4:

### Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $V\sin40 - (1.8/2)g = 0$ | M1 | Or $0 = (V\sin40)\times1.8 - g\times1.8^2/2$ |
| $V = 14(.0)$ ms$^{-1}$ | A1 [2] | |

### Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $(14\sin40)^2 = 2gh$ | M1 | Or $h = (V\sin40)\times0.9 - g\times0.9^2/2$ |
| $h = 4.05$ m | A1 [2] | |

### Part (iii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $d = (14\cos40)\times1.8$ | M1 | Or $d = V^2\sin80/g$ |
| $d = 19.3$ m | A1 [2] [6] | |

---
4 A ball $B$ is projected from a point $O$ on horizontal ground at an angle of $40 ^ { \circ }$ above the horizontal. $B$ hits the ground 1.8 s after the instant of projection. Calculate\\
(i) the speed of projection of $B$,\\
(ii) the greatest height of $B$,\\
(iii) the distance from $O$ of the point at which $B$ hits the ground.

\hfill \mbox{\textit{CAIE M2 2013 Q4 [6]}}