CAIE M2 2006 June — Question 2 5 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2006
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeToppling and sliding of solids
DifficultyStandard +0.3 This is a standard mechanics problem involving center of mass of a cone (standard result: h/4 from base), toppling condition (vertical through COM passes through edge of base), and friction inequality. All steps are routine applications of well-known principles with straightforward trigonometry and algebra. Slightly easier than average due to the structured parts guiding the solution.
Spec3.03r Friction: concept and vector form3.03t Coefficient of friction: F <= mu*R model6.04b Find centre of mass: using symmetry6.04e Rigid body equilibrium: coplanar forces

2 A uniform solid cone has height 38 cm .
  1. Write down the distance of the centre of mass of the cone from its base. \includegraphics[max width=\textwidth, alt={}, center]{ece63d46-5e56-4668-939a-9dbbcfc1a77a-2_497_547_1224_840} The cone is placed with its axis vertical on a rough horizontal plane. The plane is slowly tilted, and the cone remains in equilibrium until the angle of inclination of the plane reaches \(31 ^ { \circ }\) (see diagram), when the cone topples.
  2. Find the radius of the cone.
  3. Show that \(\mu \geqslant 0.601\), correct to 3 significant figures, where \(\mu\) is the coefficient of friction between the cone and the plane.

(i) Distance is 9.5 cm
AnswerMarks Guidance
\(\tan 31° = m/9.5\)B1, M1 For using the idea that the centre of mass is vertically above the lowest point of the base
(iii) Radius is 5.71 cm
\(F = mg \sin 31°\) and \(R = mg \cos 31°\)
or \(\mu = \tan \theta\) when on the point of slipping (may be implied)
AnswerMarks Guidance
\(\mu \geq 0.601\)A1, B1
B12 From \(F \leq \mu R\) or \(\mu \geq \tan \alpha\)
**(i)** Distance is 9.5 cm
$\tan 31° = m/9.5$ | B1, M1 | For using the idea that the centre of mass is vertically above the lowest point of the base

**(iii)** Radius is 5.71 cm
$F = mg \sin 31°$ and $R = mg \cos 31°$
or $\mu = \tan \theta$ when on the point of slipping (may be implied)
$\mu \geq 0.601$ | A1, B1
B1 | 2 | From $F \leq \mu R$ or $\mu \geq \tan \alpha$

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2 A uniform solid cone has height 38 cm .\\
(i) Write down the distance of the centre of mass of the cone from its base.\\
\includegraphics[max width=\textwidth, alt={}, center]{ece63d46-5e56-4668-939a-9dbbcfc1a77a-2_497_547_1224_840}

The cone is placed with its axis vertical on a rough horizontal plane. The plane is slowly tilted, and the cone remains in equilibrium until the angle of inclination of the plane reaches $31 ^ { \circ }$ (see diagram), when the cone topples.\\
(ii) Find the radius of the cone.\\
(iii) Show that $\mu \geqslant 0.601$, correct to 3 significant figures, where $\mu$ is the coefficient of friction between the cone and the plane.

\hfill \mbox{\textit{CAIE M2 2006 Q2 [5]}}