Question 1 - A-Level Maths

CAIE M1 2017 November — Question 1 4 marks

Exam Board	CAIE
Module	M1 (Mechanics 1)
Year	2017
Session	November
Marks	4
Paper	Download PDF ↗
Mark scheme	Download PDF ↗
Topic	Constant acceleration (SUVAT)
Type	Find acceleration from distances/times
Difficulty	Moderate -0.3 This is a straightforward application of Newton's second law with a single force at an angle, followed by standard SUVAT. The horizontal component calculation (12cos25°) and F=ma are routine, then using s=½at² with given values requires no problem-solving insight—just methodical execution of standard mechanics procedures.
Spec	3.03c Newton's second law: F=ma one dimension 3.03e Resolve forces: two dimensions

1 A block of mass 3 kg is initially at rest on a smooth horizontal floor. A force of 12 N , acting at an angle of \(25 ^ { \circ }\) above the horizontal, is applied to the block. Find the distance travelled by the block in the first 5 seconds of its motion.

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Question 1:

Answer	Marks	Guidance
Answer	Marks	Guidance
\([12\cos 25 = 3a]\)	M1	For use of Newton's second law
\(a = 4\cos 25 = 3.625\)	A1
\([s = \frac{1}{2} \times 4\cos 25 \times 5^2]\)	M1	For use of \(s = ut + \frac{1}{2}at^2\) OE
Distance \(= 45.3\) m	A1

## Question 1:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $[12\cos 25 = 3a]$ | M1 | For use of Newton's second law |
| $a = 4\cos 25 = 3.625$ | A1 | |
| $[s = \frac{1}{2} \times 4\cos 25 \times 5^2]$ | M1 | For use of $s = ut + \frac{1}{2}at^2$ OE |
| Distance $= 45.3$ m | A1 | |

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1 A block of mass 3 kg is initially at rest on a smooth horizontal floor. A force of 12 N , acting at an angle of $25 ^ { \circ }$ above the horizontal, is applied to the block. Find the distance travelled by the block in the first 5 seconds of its motion.\\

\hfill \mbox{\textit{CAIE M1 2017 Q1 [4]}}

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