CAIE M1 2016 November — Question 2 5 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2016
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMotion on a slope
TypeCoefficient of friction from motion
DifficultyModerate -0.3 This is a straightforward mechanics problem requiring standard application of Newton's second law on an inclined plane. Students use kinematics to find acceleration (a = v/t = 0.4 m/s²), then resolve forces parallel to the plane (mg sin 20° - F = ma) to verify the given friction value, and finally use F = μR with R = mg cos 20° to find μ. All steps are routine textbook procedures with no conceptual challenges beyond basic force resolution.
Spec3.03t Coefficient of friction: F <= mu*R model3.03v Motion on rough surface: including inclined planes

2 A particle of mass 0.1 kg is released from rest on a rough plane inclined at \(20 ^ { \circ }\) to the horizontal. It is given that, 5 seconds after release, the particle has a speed of \(2 \mathrm {~ms} ^ { - 1 }\).
  1. Find the acceleration of the particle and hence show that the magnitude of the frictional force acting on the particle is 0.302 N , correct to 3 significant figures.
  2. Find the coefficient of friction between the particle and the plane.

Question 2(i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(2 = 5a \rightarrow a = 0.4\text{ ms}^{-2}\)B1
\([0.1g\sin20 - F = 0.1 \times 0.4]\)M1 For applying Newton's 2nd law to the particle
\(F = 0.302\text{ N}\)A1 AG [3]
Question 2(ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\([R = 0.1g\cos20\ (= 0.9397)]\)M1 For attempting to find \(R\) and using \(\mu = F/R\)
\(\mu = 0.3020/0.9397 = 0.321\)A1 [2]
## Question 2(i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $2 = 5a \rightarrow a = 0.4\text{ ms}^{-2}$ | B1 | |
| $[0.1g\sin20 - F = 0.1 \times 0.4]$ | M1 | For applying Newton's 2nd law to the particle |
| $F = 0.302\text{ N}$ | A1 AG | [3] |

## Question 2(ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $[R = 0.1g\cos20\ (= 0.9397)]$ | M1 | For attempting to find $R$ and using $\mu = F/R$ |
| $\mu = 0.3020/0.9397 = 0.321$ | A1 | [2] |

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2 A particle of mass 0.1 kg is released from rest on a rough plane inclined at $20 ^ { \circ }$ to the horizontal. It is given that, 5 seconds after release, the particle has a speed of $2 \mathrm {~ms} ^ { - 1 }$.\\
(i) Find the acceleration of the particle and hence show that the magnitude of the frictional force acting on the particle is 0.302 N , correct to 3 significant figures.\\
(ii) Find the coefficient of friction between the particle and the plane.

\hfill \mbox{\textit{CAIE M1 2016 Q2 [5]}}