CAIE M1 2014 November — Question 1 4 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2014
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeTwo particles: same start time, different heights
DifficultyModerate -0.3 This is a straightforward two-particle SUVAT problem requiring standard application of kinematic equations with gravity. Students must find the time of flight for P using v = u + at (giving t = 2.24s), then use this to find h and V for Q using standard equations. All steps are routine with no conceptual challenges beyond recognizing both particles have the same time of flight.
Spec3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form

1 A particle \(P\) is projected vertically upwards with speed \(11 \mathrm {~ms} ^ { - 1 }\) from a point on horizontal ground. At the same instant a particle \(Q\) is released from rest at a point \(h \mathrm {~m}\) above the ground. \(P\) and \(Q\) hit the ground at the same instant, when \(Q\) has speed \(V \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  1. Find the time after projection at which \(P\) hits the ground.
  2. Hence find the values of \(h\) and \(V\).

Question 1:
Part (i):
AnswerMarks Guidance
WorkingMark Guidance
\([-11 = 11 - 10t]\)M1 For using \(v = u - gt\) (or equivalent method) to find duration of motion
Time after projection is 2.2 secondsA1 2 marks total
Part (ii):
AnswerMarks Guidance
WorkingMark Guidance
\(h = 0 + \frac{1}{2}g \times 2.2^2 = 24.2\)B1\(\checkmark\)
\(V = 0 + g \times 2.2 = 22\)B1\(\checkmark\) 2 marks total
## Question 1:

### Part (i):
| Working | Mark | Guidance |
|---------|------|----------|
| $[-11 = 11 - 10t]$ | M1 | For using $v = u - gt$ (or equivalent method) to find duration of motion |
| Time after projection is 2.2 seconds | A1 | 2 marks total |

### Part (ii):
| Working | Mark | Guidance |
|---------|------|----------|
| $h = 0 + \frac{1}{2}g \times 2.2^2 = 24.2$ | B1$\checkmark$ | |
| $V = 0 + g \times 2.2 = 22$ | B1$\checkmark$ | 2 marks total |

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1 A particle $P$ is projected vertically upwards with speed $11 \mathrm {~ms} ^ { - 1 }$ from a point on horizontal ground. At the same instant a particle $Q$ is released from rest at a point $h \mathrm {~m}$ above the ground. $P$ and $Q$ hit the ground at the same instant, when $Q$ has speed $V \mathrm {~m} \mathrm {~s} ^ { - 1 }$.\\
(i) Find the time after projection at which $P$ hits the ground.\\
(ii) Hence find the values of $h$ and $V$.

\hfill \mbox{\textit{CAIE M1 2014 Q1 [4]}}