CAIE M1 2013 November — Question 3 6 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2013
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMotion on a slope
TypeVehicle on slope with resistance
DifficultyModerate -0.3 This is a straightforward mechanics problem requiring Newton's second law on an inclined plane with given resistance. Part (i) involves resolving forces and substituting known values into F = ma. Part (ii) uses standard kinematics (v² = u² + 2as). Both parts are routine applications of standard M1 techniques with no conceptual challenges or novel problem-solving required, making it slightly easier than average.
Spec3.02d Constant acceleration: SUVAT formulae3.03d Newton's second law: 2D vectors6.02a Work done: concept and definition

3 A cyclist exerts a constant driving force of magnitude \(F \mathrm {~N}\) while moving up a straight hill inclined at an angle \(\alpha\) to the horizontal, where \(\sin \alpha = \frac { 36 } { 325 }\). A constant resistance to motion of 32 N acts on the cyclist. The total weight of the cyclist and his bicycle is 780 N . The cyclist's acceleration is \(- 0.2 \mathrm {~m} \mathrm {~s} ^ { - 2 }\).
  1. Find the value of \(F\). The cyclist's speed is \(7 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) at the bottom of the hill.
  2. Find how far up the hill the cyclist travels before coming to rest.

Question 3:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
M1For applying Newton's 2nd law to the bicycle/cyclist
\(F - 780 \times (36 \div 325) - 32 = 78 \times (-0.2)\)A2 A2 for all correct, A1 for one error, A0 for more than one error
\(F = 103\) (\(102.8\) exact)A1 [4]
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(0 = 7^2 + 2(-0.2)s\)M1 For using \(0 = u^2 + 2as\)
Distance is \(122.5\) m (accept 122 or 123)A1 [2]
## Question 3:

### Part (i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| | M1 | For applying Newton's 2nd law to the bicycle/cyclist |
| $F - 780 \times (36 \div 325) - 32 = 78 \times (-0.2)$ | A2 | A2 for all correct, A1 for one error, A0 for more than one error |
| $F = 103$ ($102.8$ exact) | A1 [4] | |

### Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $0 = 7^2 + 2(-0.2)s$ | M1 | For using $0 = u^2 + 2as$ |
| Distance is $122.5$ m (accept 122 or 123) | A1 [2] | |

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3 A cyclist exerts a constant driving force of magnitude $F \mathrm {~N}$ while moving up a straight hill inclined at an angle $\alpha$ to the horizontal, where $\sin \alpha = \frac { 36 } { 325 }$. A constant resistance to motion of 32 N acts on the cyclist. The total weight of the cyclist and his bicycle is 780 N . The cyclist's acceleration is $- 0.2 \mathrm {~m} \mathrm {~s} ^ { - 2 }$.\\
(i) Find the value of $F$.

The cyclist's speed is $7 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ at the bottom of the hill.\\
(ii) Find how far up the hill the cyclist travels before coming to rest.

\hfill \mbox{\textit{CAIE M1 2013 Q3 [6]}}