Moderate -0.3 This is a straightforward two-stage SUVAT problem: first find the time for vertical free fall using s=ut+½at², then use that time to find horizontal distance traveled by P using the same equation. Both parts use standard kinematic equations with given values, requiring only careful substitution and arithmetic. Slightly easier than average due to its direct application of formulas without conceptual complications.
1 An object is released from rest at a height of 125 m above horizontal ground and falls freely under gravity, hitting a moving target \(P\). The target \(P\) is moving on the ground in a straight line, with constant acceleration \(0.8 \mathrm {~m} \mathrm {~s} ^ { - 2 }\). At the instant the object is released \(P\) passes through a point \(O\) with speed \(5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). Find the distance from \(O\) to the point where \(P\) is hit by the object.
1 An object is released from rest at a height of 125 m above horizontal ground and falls freely under gravity, hitting a moving target $P$. The target $P$ is moving on the ground in a straight line, with constant acceleration $0.8 \mathrm {~m} \mathrm {~s} ^ { - 2 }$. At the instant the object is released $P$ passes through a point $O$ with speed $5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. Find the distance from $O$ to the point where $P$ is hit by the object.
\hfill \mbox{\textit{CAIE M1 2012 Q1 [4]}}