CAIE M1 2009 November — Question 4 7 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2009
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMotion on a slope
TypeParticle just remains at rest
DifficultyStandard +0.3 This is a standard M1 mechanics problem requiring resolution of forces on an inclined plane and application of friction laws. Part (i) uses N=mg cos α, part (ii) applies F=ma with friction opposing motion, and part (iii) compares limiting friction with the component down the slope—all routine techniques with straightforward arithmetic given the numerical values.
Spec3.03i Normal reaction force3.03t Coefficient of friction: F <= mu*R model3.03v Motion on rough surface: including inclined planes

4 A particle moves up a line of greatest slope of a rough plane inclined at an angle \(\alpha\) to the horizontal, where \(\cos \alpha = 0.96\) and \(\sin \alpha = 0.28\).
  1. Given that the normal component of the contact force acting on the particle has magnitude 1.2 N , find the mass of the particle.
  2. Given also that the frictional component of the contact force acting on the particle has magnitude 0.4 N , find the deceleration of the particle. The particle comes to rest on reaching the point \(X\).
  3. Determine whether the particle remains at \(X\) or whether it starts to move down the plane.

AnswerMarks Guidance
Part (i)
\([1.2 = mg \cos\alpha]\)M1 For resolving forces normal to the plane
Mass is 0.125 kgA1 2
Part (ii)
\([-mg \sin\alpha - F = ma]\)M1 For using Newton's second law
\(- 0.125 \times 10 \times 0.28 - 0.4 = -0.125a\)A1ft
\(a = -6 \Rightarrow\) deceleration is 6 m s\(^{-2}\)A1 3
Part (iii)
\(\mu R > mg \sin\alpha \Rightarrow\) particle remains at restM1 For comparing magnitudes of \(\mu R\) (0.4) and \(mg \sin\alpha\) (0.35)
A12
| **Part (i)** | | |
|---|---|---|
| $[1.2 = mg \cos\alpha]$ | M1 | For resolving forces normal to the plane |
| Mass is 0.125 kg | A1 | 2 |

| **Part (ii)** | | |
|---|---|---|
| $[-mg \sin\alpha - F = ma]$ | M1 | For using Newton's second law |
| $- 0.125 \times 10 \times 0.28 - 0.4 = -0.125a$ | A1ft | |
| $a = -6 \Rightarrow$ deceleration is 6 m s$^{-2}$ | A1 | 3 | ft incorrect mass |

| **Part (iii)** | | |
|---|---|---|
| $\mu R > mg \sin\alpha \Rightarrow$ particle remains at rest | M1 | For comparing magnitudes of $\mu R$ (0.4) and $mg \sin\alpha$ (0.35) |
| | A1 | 2 |
4 A particle moves up a line of greatest slope of a rough plane inclined at an angle $\alpha$ to the horizontal, where $\cos \alpha = 0.96$ and $\sin \alpha = 0.28$.\\
(i) Given that the normal component of the contact force acting on the particle has magnitude 1.2 N , find the mass of the particle.\\
(ii) Given also that the frictional component of the contact force acting on the particle has magnitude 0.4 N , find the deceleration of the particle.

The particle comes to rest on reaching the point $X$.\\
(iii) Determine whether the particle remains at $X$ or whether it starts to move down the plane.

\hfill \mbox{\textit{CAIE M1 2009 Q4 [7]}}