CAIE M1 2005 November — Question 1 4 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2005
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeFind acceleration from distances/times
DifficultyModerate -0.3 This is a straightforward SUVAT question requiring application of v² = u² + 2as twice, then algebraic manipulation to eliminate 'a'. While it involves multiple steps and algebraic unknowns, the approach is standard and mechanical—students simply apply a familiar formula twice and solve simultaneously. Slightly easier than average due to the clear structure and routine nature of the technique.
Spec3.02d Constant acceleration: SUVAT formulae

1 A car travels in a straight line with constant acceleration \(a \mathrm {~m} \mathrm {~s} ^ { - 2 }\). It passes the points \(A , B\) and \(C\), in this order, with speeds \(5 \mathrm {~m} \mathrm {~s} ^ { - 1 } , 7 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and \(8 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) respectively. The distances \(A B\) and \(B C\) are \(d _ { 1 } \mathrm {~m}\) and \(d _ { 2 } \mathrm {~m}\) respectively.
  1. Write down an equation connecting
    1. \(d _ { 1 }\) and \(a\),
    2. \(d _ { 2 }\) and \(a\).
    3. Hence find \(d _ { 1 }\) in terms of \(d _ { 2 }\).

Question 1:
Part (i)
AnswerMarks Guidance
Answer/WorkingMark Guidance
(a) \(7^2 - 5^2 = 2ad_1\)M1 For using \(v^2 = u^2 + 2as\)
(b) \(8^2 - 7^2 = 2ad_2\)A1
Part (ii)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\frac{24}{15} = \frac{d_1}{d_2}\)M1 For eliminating \(a\)
\(d_1 = 1.6d_2\)A1
## Question 1:

### Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| (a) $7^2 - 5^2 = 2ad_1$ | M1 | For using $v^2 = u^2 + 2as$ |
| (b) $8^2 - 7^2 = 2ad_2$ | A1 | |

### Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\frac{24}{15} = \frac{d_1}{d_2}$ | M1 | For eliminating $a$ |
| $d_1 = 1.6d_2$ | A1 | |

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1 A car travels in a straight line with constant acceleration $a \mathrm {~m} \mathrm {~s} ^ { - 2 }$. It passes the points $A , B$ and $C$, in this order, with speeds $5 \mathrm {~m} \mathrm {~s} ^ { - 1 } , 7 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and $8 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ respectively. The distances $A B$ and $B C$ are $d _ { 1 } \mathrm {~m}$ and $d _ { 2 } \mathrm {~m}$ respectively.\\
(i) Write down an equation connecting
\begin{enumerate}[label=(\alph*)]
\item $d _ { 1 }$ and $a$,
\item $d _ { 2 }$ and $a$.\\
(ii) Hence find $d _ { 1 }$ in terms of $d _ { 2 }$.
\end{enumerate}

\hfill \mbox{\textit{CAIE M1 2005 Q1 [4]}}