CAIE M1 2018 June — Question 1 4 marks

Exam BoardCAIE
ModuleM1 (Mechanics 1)
Year2018
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
TypeEnergy method - driving force on horizontal road
DifficultyModerate -0.3 This is a straightforward work-energy problem requiring application of the work-energy principle with two components: kinetic energy change and work against resistance. The calculation involves standard formulas (KE = ½mv², work = force × distance) with clear given values and a single unknown, making it slightly easier than average but still requiring proper setup of the energy equation.
Spec6.02b Calculate work: constant force, resolved component6.02i Conservation of energy: mechanical energy principle

1 A man has mass 80 kg . He runs along a horizontal road against a constant resistance force of magnitude \(P \mathrm {~N}\). The total work done by the man in increasing his speed from \(4 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) to \(5.5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) while running a distance of 60 metres is 1200 J . Find the value of \(P\).

Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
KE gain \(= \frac{1}{2} \times 80 \times (5.5^2 - 4^2)\) \([= 570]\)B1 Either initial or final KE correct
WD against Res \(= 60P\)B1
\([\frac{1}{2} \times 80 \times (5.5^2 - 4^2) + 60P = 1200]\)M1 Four term work-energy equation
\(P = 10.5\)A1
Total: 4
**Question 1:**

| Answer | Marks | Guidance |
|--------|-------|----------|
| KE gain $= \frac{1}{2} \times 80 \times (5.5^2 - 4^2)$ $[= 570]$ | B1 | Either initial or final KE correct |
| WD against Res $= 60P$ | B1 | |
| $[\frac{1}{2} \times 80 \times (5.5^2 - 4^2) + 60P = 1200]$ | M1 | Four term work-energy equation |
| $P = 10.5$ | A1 | |
| **Total: 4** | | |

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1 A man has mass 80 kg . He runs along a horizontal road against a constant resistance force of magnitude $P \mathrm {~N}$. The total work done by the man in increasing his speed from $4 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ to $5.5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ while running a distance of 60 metres is 1200 J . Find the value of $P$.\\

\hfill \mbox{\textit{CAIE M1 2018 Q1 [4]}}