Edexcel AEA 2011 June — Question 1

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2011
SessionJune
PaperDownload PDF ↗
TopicStandard trigonometric equations
TypeTransformed argument solving
DifficultyStandard +0.3 This is a straightforward trigonometric equation requiring the identity cot(x) = tan(90° - x), leading to a simple linear equation in θ. Despite being from AEA, it's a routine 4-mark question with minimal steps and no novel insight required—slightly easier than average.
Spec1.05i Inverse trig functions: arcsin, arccos, arctan domains and graphs1.05o Trigonometric equations: solve in given intervals

Solve for \(0 \leq \theta \leq 180°\) $$\tan(\theta + 35°) = \cot(\theta - 53°)$$ [Total 4 marks]

Solve for $0 \leq \theta \leq 180°$

$$\tan(\theta + 35°) = \cot(\theta - 53°)$$
[Total 4 marks]

\hfill \mbox{\textit{Edexcel AEA 2011 Q1}}