Pre-U Pre-U 9794/3 2014 June — Question 10 10 marks

Exam BoardPre-U
ModulePre-U 9794/3 (Pre-U Mathematics Paper 3)
Year2014
SessionJune
Marks10
TopicVariable acceleration (1D)
TypeVariable acceleration with initial conditions
DifficultyModerate -0.3 This is a straightforward kinematics question requiring integration of acceleration to find velocity and displacement, with standard initial conditions. While it involves multiple steps and interpreting when the particle returns to O (requiring solving a quadratic), these are routine A-level mechanics techniques with no novel problem-solving required. Slightly easier than average due to the simple polynomial form and clear structure.
Spec3.02d Constant acceleration: SUVAT formulae3.02f Non-uniform acceleration: using differentiation and integration

A particle \(P\) is free to move along a straight line \(Ox\). It starts from rest at \(O\) and after \(t\) seconds its acceleration \(a \mathrm{~m} \mathrm{~s}^{-2}\) is given by \(a = 12 - 6t\).
  1. Find an expression in terms of \(t\) for its velocity \(v \mathrm{~m} \mathrm{~s}^{-1}\). Hence find the velocity of \(P\) when \(t = 4\). [4]
  2. Find the displacement of \(P\) from \(O\) when \(t = 4\). [3]
  3. Find the velocity of \(P\) when it returns to \(O\). [3]

A particle $P$ is free to move along a straight line $Ox$. It starts from rest at $O$ and after $t$ seconds its acceleration $a \mathrm{~m} \mathrm{~s}^{-2}$ is given by $a = 12 - 6t$.

\begin{enumerate}[label=(\roman*)]
\item Find an expression in terms of $t$ for its velocity $v \mathrm{~m} \mathrm{~s}^{-1}$. Hence find the velocity of $P$ when $t = 4$. [4]
\item Find the displacement of $P$ from $O$ when $t = 4$. [3]
\item Find the velocity of $P$ when it returns to $O$. [3]
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/3 2014 Q10 [10]}}