| Exam Board | Pre-U |
|---|---|
| Module | Pre-U 9794/3 (Pre-U Mathematics Paper 3) |
| Year | 2013 |
| Session | November |
| Marks | 9 |
| Topic | Projectiles |
| Type | Horizontal projection from height |
| Difficulty | Moderate -0.3 This is a standard projectile motion problem with horizontal launch requiring basic SUVAT equations in two dimensions. Part (i) involves straightforward calculation of vertical drop over given horizontal distance, while part (ii) requires finding range - both are routine mechanics applications with no conceptual challenges beyond A-level core content. |
| Spec | 3.02i Projectile motion: constant acceleration model |
A tennis ball is served horizontally at a speed of 24 m s$^{-1}$ from a height of 2.45 m above the ground.
\begin{enumerate}[label=(\roman*)]
\item Show that it will clear the net at a point where the net is 1 m high and 12 m from the server. [5]
\item How far beyond the net will it land? [4]
\end{enumerate}
\hfill \mbox{\textit{Pre-U Pre-U 9794/3 2013 Q9 [9]}}