Pre-U Pre-U 9794/2 2011 June — Question 7 9 marks

Exam BoardPre-U
ModulePre-U 9794/2 (Pre-U Mathematics Paper 2)
Year2011
SessionJune
Marks9
TopicComposite & Inverse Functions
TypeDetermine if inverse exists
DifficultyModerate -0.3 This question tests standard A-level concepts: determining invertibility (one-to-one test), finding range by completing the square, applying a double angle identity, and sketching a transformed trigonometric function. All parts are routine applications of well-practiced techniques with no novel problem-solving required, making it slightly easier than average but not trivial due to the multi-part nature and need for clear reasoning.
Spec1.02m Graphs of functions: difference between plotting and sketching1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence1.02w Graph transformations: simple transformations of f(x)1.05l Double angle formulae: and compound angle formulae

Functions f, g and h are defined for \(x \in \mathbb{R}\) by $$f : x \mapsto x^2 - 2x,$$ $$g : x \mapsto x^2,$$ $$h : x \mapsto \sin x.$$
    1. State whether or not f has an inverse, giving a reason. [2]
    2. Determine the range of the function f. [2]
    1. Show that gh(x) can be expressed as \(\frac{1}{2}(1 - \cos 2x)\). [2]
    2. Sketch the curve C defined by \(y = \text{gh}(x)\) for \(0 \leqslant x \leqslant 2\pi\). [3]

Part (i)
AnswerMarks Guidance
(a) Not invertibleB1
Not 1–1 or equivalentB1 [2]
(b) (Minimum value of –1 at \(x = 1\))B1
\(-1 \le f(x)\)B1
[B1 for correct interval; B1 for correct inequality][2]
Part (ii)
AnswerMarks Guidance
(a) \(gh(x) = \sin^2 x\)B1
Obtain \(\frac{1}{2}(1 - \cos 2x)\) with some workingAG B1
(b) Sine waveM1
Period of \(\pi\)A1
Completely correctA1 [3]
**Part (i)**
**(a)** Not invertible | B1
Not 1–1 or equivalent | B1 | [2]

**(b)** (Minimum value of –1 at $x = 1$) | B1
$-1 \le f(x)$ | B1
[B1 for correct interval; B1 for correct inequality] | [2]

**Part (ii)**
**(a)** $gh(x) = \sin^2 x$ | B1
Obtain $\frac{1}{2}(1 - \cos 2x)$ with some working | AG | B1 | [2]

**(b)** Sine wave | M1
Period of $\pi$ | A1
Completely correct | A1 | [3]
Functions f, g and h are defined for $x \in \mathbb{R}$ by
$$f : x \mapsto x^2 - 2x,$$
$$g : x \mapsto x^2,$$
$$h : x \mapsto \sin x.$$

\begin{enumerate}[label=(\roman*)]
\item \begin{enumerate}[label=(\alph*)]
\item State whether or not f has an inverse, giving a reason. [2]
\item Determine the range of the function f. [2]
\end{enumerate}
\item \begin{enumerate}[label=(\alph*)]
\item Show that gh(x) can be expressed as $\frac{1}{2}(1 - \cos 2x)$. [2]
\item Sketch the curve C defined by $y = \text{gh}(x)$ for $0 \leqslant x \leqslant 2\pi$. [3]
\end{enumerate}
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/2 2011 Q7 [9]}}