Pre-U Pre-U 9794/1 2010 June — Question 12 7 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2010
SessionJune
Marks7
TopicProbability Definitions
TypeCombined event algebra
DifficultyModerate -0.3 This question tests standard probability rules (complement rule, conditional probability) and basic combinatorics (combinations formula). Part (a) requires straightforward application of P(A∪B) = 1 - P(A'∩B') and P(A∩B) = P(A|B)×P(B), while part (b) is direct application of C(49,6). All techniques are routine A-level content with no problem-solving insight required, making it slightly easier than average.
Spec2.03a Mutually exclusive and independent events2.03d Calculate conditional probability: from first principles5.01a Permutations and combinations: evaluate probabilities

  1. Events \(A\) and \(B\) are such that \(\mathrm{P}(A' \cap B') = \frac{1}{6}\).
    1. Find \(\mathrm{P}(A \cup B)\). [2]
    2. Given that \(\mathrm{P}(A | B) = \frac{1}{4}\) and \(\mathrm{P}(B) = \frac{1}{3}\), find \(\mathrm{P}(A \cap B)\) and \(\mathrm{P}(A)\). [3]
  2. In playing the UK Lottery, a set of 6 different integers is chosen irrespective of order from the integers 1 to 49 inclusive. How many different sets of 6 integers can be chosen? [2]

AnswerMarks Guidance
(a) (i) \(P(A \cup B) = 1 - P(A' \cap B')\)M1
\(= \frac{5}{6}\)A1 [2]
(ii) State \(P(A \cap B) = P(AB)P(B) = \frac{1}{12}\) B1
Use \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\) aefM1
\(= \frac{2}{3}\)A1 [3]
(b) \(\frac{49!}{43!6!} = 13\,983\,816\)M1 A1 [2]
(a) (i) $P(A \cup B) = 1 - P(A' \cap B')$ | M1 |
$= \frac{5}{6}$ | A1 | [2]

(ii) State $P(A \cap B) = P(A|B)P(B) = \frac{1}{12}$ | B1 |
Use $P(A \cup B) = P(A) + P(B) - P(A \cap B)$ aef | M1 |
$= \frac{2}{3}$ | A1 | [3]

(b) $\frac{49!}{43!6!} = 13\,983\,816$ | M1 A1 | [2]
\begin{enumerate}[label=(\alph*)]
\item Events $A$ and $B$ are such that $\mathrm{P}(A' \cap B') = \frac{1}{6}$.

\begin{enumerate}[label=(\roman*)]
\item Find $\mathrm{P}(A \cup B)$. [2]

\item Given that $\mathrm{P}(A | B) = \frac{1}{4}$ and $\mathrm{P}(B) = \frac{1}{3}$, find $\mathrm{P}(A \cap B)$ and $\mathrm{P}(A)$. [3]
\end{enumerate}

\item In playing the UK Lottery, a set of 6 different integers is chosen irrespective of order from the integers 1 to 49 inclusive. How many different sets of 6 integers can be chosen? [2]
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2010 Q12 [7]}}