Moderate -0.8 This is a straightforward equilibrium problem requiring students to set the sum of forces equal to zero and solve two simultaneous linear equations for a and b. It's a standard textbook exercise with routine algebraic manipulation, making it easier than average for A-level mechanics.
Three forces \(\mathbf{F}_1\), \(\mathbf{F}_2\) and \(\mathbf{F}_3\) acting on a particle are given by
$$\mathbf{F}_1 = (3\mathbf{i} - 2a\mathbf{j})\text{N}, \quad \mathbf{F}_2 = (2b\mathbf{i} + 3a\mathbf{j})\text{N} \quad \text{and} \quad \mathbf{F}_3 = (-2\mathbf{i} + b\mathbf{j})\text{N}.$$
The particle is in equilibrium under the action of these three forces.
Find the value of \(a\) and the value of \(b\). [3]
Three forces $\mathbf{F}_1$, $\mathbf{F}_2$ and $\mathbf{F}_3$ acting on a particle are given by
$$\mathbf{F}_1 = (3\mathbf{i} - 2a\mathbf{j})\text{N}, \quad \mathbf{F}_2 = (2b\mathbf{i} + 3a\mathbf{j})\text{N} \quad \text{and} \quad \mathbf{F}_3 = (-2\mathbf{i} + b\mathbf{j})\text{N}.$$
The particle is in equilibrium under the action of these three forces.
Find the value of $a$ and the value of $b$. [3]
\hfill \mbox{\textit{OCR H240/03 2018 Q7 [3]}}