OCR Further Pure Core 2 2018 December — Question 4 6 marks

Exam BoardOCR
ModuleFurther Pure Core 2 (Further Pure Core 2)
Year2018
SessionDecember
Marks6
TopicLinear transformations
Type3D transformation matrices
DifficultyStandard +0.3 This is a straightforward Further Maths question on 3D transformations. Part (a) requires recognizing that a diagonal matrix with eigenvalues 1,1,-1 reflects in a coordinate plane (immediate from inspection). Part (b) uses the reflection property that the middle eigenvalue must equal -1, giving a simple quadratic. Part (c) asks for conceptual understanding that reflections are self-inverse. All parts are direct applications of standard theory with minimal computation or insight required.
Spec4.03f Linear transformations 3D: reflections and rotations about axes4.03i Determinant: area scale factor and orientation

You are given that the matrix \(\mathbf{A} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & \frac{2a-a^2}{3} & 0 \\ 0 & 0 & 1 \end{pmatrix}\), where \(a\) is a positive constant, represents the transformation R which is a reflection in 3-D.
  1. State the plane of reflection of R. [1]
  2. Determine the value of \(a\). [3]
  3. With reference to R explain why \(\mathbf{A}^2 = \mathbf{I}\), the \(3\times 3\) identity matrix. [2]

AnswerMarks Guidance
(a) The x-z planeB1 or \(y = 0\)
(b) \(\frac{2a - a^2}{3} = -1\)B1
\(a^2 - 2a - 3 = 0 \Rightarrow a = -1, 3\)M1 BC. Rearranging the quadratic equation and solving.
\(a > 0 \Rightarrow a = 3\)A1
(c) Any reflection is self-inverse... oeB1 eg "If you do a reflection twice it gets back to where it started"
...\(\text{so } A^2 = AA^{-1} = I\)B1
**(a)** The x-z plane | B1 | or $y = 0$

**(b)** $\frac{2a - a^2}{3} = -1$ | B1 |

$a^2 - 2a - 3 = 0 \Rightarrow a = -1, 3$ | M1 | BC. Rearranging the quadratic equation and solving.

$a > 0 \Rightarrow a = 3$ | A1 |

**(c)** Any reflection is self-inverse... oe | B1 | eg "If you do a reflection twice it gets back to where it started"

...$\text{so } A^2 = AA^{-1} = I$ | B1 |

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You are given that the matrix $\mathbf{A} = \begin{pmatrix} 1 & 0 & 0 \\ 0 & \frac{2a-a^2}{3} & 0 \\ 0 & 0 & 1 \end{pmatrix}$, where $a$ is a positive constant, represents the transformation R which is a reflection in 3-D.

\begin{enumerate}[label=(\alph*)]
\item State the plane of reflection of R. [1]

\item Determine the value of $a$. [3]

\item With reference to R explain why $\mathbf{A}^2 = \mathbf{I}$, the $3\times 3$ identity matrix. [2]
\end{enumerate}

\hfill \mbox{\textit{OCR Further Pure Core 2 2018 Q4 [6]}}