OCR Further Pure Core 2 2021 June — Question 3 7 marks

Exam BoardOCR
ModuleFurther Pure Core 2 (Further Pure Core 2)
Year2021
SessionJune
Marks7
TopicSecond order differential equations
TypeModeling context with interpretation
DifficultyStandard +0.3 This is a standard second-order linear homogeneous differential equation with constant coefficients. Students solve the auxiliary equation (m-5)(m+3)=0, apply the boundary conditions Q(0)=100 and the finite limit condition (which forces the coefficient of e^{5t} to be zero), then substitute t=0.5. While it requires multiple steps, it follows a completely routine procedure taught explicitly in FP2 with no novel problem-solving required.
Spec4.10d Second order homogeneous: auxiliary equation method

A capacitor is an electrical component which stores charge. The value of the charge stored by the capacitor, in suitable units, is denoted by \(Q\). The capacitor is placed in an electrical circuit. At any time \(t\) seconds, where \(t \geq 0\), \(Q\) can be modelled by the differential equation $$\frac{d^2Q}{dt^2} - 2\frac{dQ}{dt} - 15Q = 0.$$ Initially the charge is 100 units and it is given that \(Q\) tends to a finite limit as \(t\) tends to infinity.
  1. Determine the charge on the capacitor when \(t = 0.5\). [6]
  2. Determine the finite limit of \(Q\) as \(t\) tends to infinity. [1]

A capacitor is an electrical component which stores charge. The value of the charge stored by the capacitor, in suitable units, is denoted by $Q$. The capacitor is placed in an electrical circuit.

At any time $t$ seconds, where $t \geq 0$, $Q$ can be modelled by the differential equation

$$\frac{d^2Q}{dt^2} - 2\frac{dQ}{dt} - 15Q = 0.$$

Initially the charge is 100 units and it is given that $Q$ tends to a finite limit as $t$ tends to infinity.

\begin{enumerate}[label=(\alph*)]
\item Determine the charge on the capacitor when $t = 0.5$. [6]
\item Determine the finite limit of $Q$ as $t$ tends to infinity. [1]
\end{enumerate}

\hfill \mbox{\textit{OCR Further Pure Core 2 2021 Q3 [7]}}