| Exam Board | OCR |
|---|---|
| Module | FM1 AS (Further Mechanics 1 AS) |
| Year | 2021 |
| Session | June |
| Marks | 5 |
| Topic | Power and driving force |
| Type | Find steady/maximum speed given power |
| Difficulty | Moderate -0.3 This is a straightforward Further Mechanics question applying P=Fv and F=ma with constant resistance. Part (a) requires equating driving force to resistance at constant speed (2 marks of routine calculation). Part (b) applies Newton's second law with power-derived force (3 marks but still standard method). While FM1 content, both parts follow textbook procedures with no problem-solving insight needed, making it slightly easier than average overall. |
| Spec | 6.02l Power and velocity: P = Fv |
A car of mass 1200 kg is driven on a long straight horizontal road. There is a constant force of 250 N resisting the motion of the car. The engine of the car is working at a constant power of 10 kW.
\begin{enumerate}[label=(\alph*)]
\item The car can travel at constant speed $v \text{ ms}^{-1}$ along the road. Find $v$. [2]
\item Find the acceleration of the car at an instant when its speed is $30 \text{ ms}^{-1}$. [3]
\end{enumerate}
\hfill \mbox{\textit{OCR FM1 AS 2021 Q1 [5]}}