SPS SPS FM Pure 2025 September — Question 4 13 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2025
SessionSeptember
Marks13
TopicParametric curves and Cartesian conversion
TypeFind normal equation
DifficultyStandard +0.8 This is a substantial parametric curves question requiring dy/dx calculation, normal line equation, and solving a simultaneous system of parametric and linear equations. Part (c) demands algebraic manipulation with trigonometric identities and careful solution of a non-trivial system, going beyond routine textbook exercises. The multi-step nature and need for exact coordinates elevate this above average difficulty.
Spec1.03g Parametric equations: of curves and conversion to cartesian1.07s Parametric and implicit differentiation

The curve \(C\) has parametric equations $$x = 2\cos t, \quad y = \sqrt{3}\cos 2t, \quad 0 \leq t \leq \pi$$
  1. Find an expression for \(\frac{dy}{dx}\) in terms of \(t\). [2]
The point \(P\) lies on \(C\) where \(t = \frac{2\pi}{3}\) The line \(l\) is the normal to \(C\) at \(P\).
  1. Show that an equation for \(l\) is $$2x - 2\sqrt{3}y - 1 = 0$$ [5]
The line \(l\) intersects the curve \(C\) again at the point \(Q\).
  1. Find the exact coordinates of \(Q\). You must show clearly how you obtained your answers. [6]

The curve $C$ has parametric equations
$$x = 2\cos t, \quad y = \sqrt{3}\cos 2t, \quad 0 \leq t \leq \pi$$

\begin{enumerate}[label=(\alph*)]
\item Find an expression for $\frac{dy}{dx}$ in terms of $t$. [2]
\end{enumerate}

The point $P$ lies on $C$ where $t = \frac{2\pi}{3}$

The line $l$ is the normal to $C$ at $P$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Show that an equation for $l$ is
$$2x - 2\sqrt{3}y - 1 = 0$$ [5]
\end{enumerate}

The line $l$ intersects the curve $C$ again at the point $Q$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Find the exact coordinates of $Q$.

You must show clearly how you obtained your answers. [6]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Pure 2025 Q4 [13]}}