SPS SPS FM Pure 2023 September — Question 7 8 marks

Exam BoardSPS
ModuleSPS FM Pure (SPS FM Pure)
Year2023
SessionSeptember
Marks8
TopicTrig Proofs
TypeSolve equation using proven identity
DifficultyStandard +0.8 Part (a) requires algebraic manipulation with reciprocal trig identities and finding a common denominator—moderately technical but standard Further Maths fare. Part (b) requires recognizing how to apply the proven identity, rearranging to use it, then solving a compound angle equation over an extended interval requiring careful consideration of periodicity. The multi-step nature, compound angle work, and need for strategic insight to connect parts (a) and (b) place this above average difficulty but not at the extreme end for Further Maths.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.05o Trigonometric equations: solve in given intervals

  1. Prove the identity \(\frac{\cos x}{\sec x + 1} + \frac{\cos x}{\sec x - 1} = 2\cot^2 x\) [3 marks]
  2. Hence, solve the equation $$\frac{\cos\left(2\theta + \frac{\pi}{3}\right)}{\sec\left(2\theta + \frac{\pi}{3}\right) + 1} = \cot\left(2\theta + \frac{\pi}{3}\right) - \frac{\cos\left(2\theta + \frac{\pi}{3}\right)}{\sec\left(2\theta + \frac{\pi}{3}\right) - 1}$$ in the interval \(0 \leq \theta \leq 2\pi\), giving your values of \(\theta\) to three significant figures where appropriate. [5 marks]

\begin{enumerate}[label=(\alph*)]
\item Prove the identity $\frac{\cos x}{\sec x + 1} + \frac{\cos x}{\sec x - 1} = 2\cot^2 x$ [3 marks]

\item Hence, solve the equation
$$\frac{\cos\left(2\theta + \frac{\pi}{3}\right)}{\sec\left(2\theta + \frac{\pi}{3}\right) + 1} = \cot\left(2\theta + \frac{\pi}{3}\right) - \frac{\cos\left(2\theta + \frac{\pi}{3}\right)}{\sec\left(2\theta + \frac{\pi}{3}\right) - 1}$$

in the interval $0 \leq \theta \leq 2\pi$, giving your values of $\theta$ to three significant figures where appropriate. [5 marks]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Pure 2023 Q7 [8]}}