| Exam Board | SPS |
|---|---|
| Module | SPS SM Mechanics (SPS SM Mechanics) |
| Year | 2021 |
| Session | September |
| Marks | 8 |
| Topic | Constant acceleration (SUVAT) |
| Difficulty | Easy -1.3 This is a straightforward kinematics problem requiring only basic SUVAT equations and velocity-time graph interpretation. Part (a) involves routine sketching with one calculation (v = u + at = 0 + 11×8 = 88 m/s). Part (b) requires calculating areas under the graph (trapezium areas) and solving a linear equation. No problem-solving insight needed, just direct application of standard AS-level mechanics techniques. |
| Spec | 3.02b Kinematic graphs: displacement-time and velocity-time3.02c Interpret kinematic graphs: gradient and area3.02d Constant acceleration: SUVAT formulae |
A racing car starts from rest at the point $A$ and moves with constant acceleration of $11 \text{ m s}^{-2}$ for $8 \text{ s}$. The velocity it has reached after $8 \text{ s}$ is then maintained for $7 \text{ s}$. The racing car then decelerates from this velocity to $40 \text{ m s}^{-1}$ in a further $2 \text{ s}$, reaching point $B$.
\begin{enumerate}[label=(\alph*)]
\item Sketch a velocity-time graph to illustrate the motion of the racing car. Include the top speed of the racing car in your sketch. [5]
\item Given that the distance between $A$ and $B$ is $1404 \text{ m}$, find the value of $T$. [3]
\end{enumerate}
\hfill \mbox{\textit{SPS SPS SM Mechanics 2021 Q1 [8]}}