SPS SPS FM Mechanics 2021 September — Question 5 8 marks

Exam BoardSPS
ModuleSPS FM Mechanics (SPS FM Mechanics)
Year2021
SessionSeptember
Marks8
TopicMotion on a slope
TypeHorizontal force on slope
DifficultyStandard +0.3 This is a two-part mechanics question involving limiting equilibrium and forces on an inclined plane. Part (a) is a standard textbook exercise requiring resolution of forces and μ = tan(30°). Part (b) requires resolving forces with an additional horizontal force, finding net force and acceleration, then using kinematics—all routine techniques for FM mechanics students. The 8 total marks reflect straightforward application of standard methods rather than any novel problem-solving.
Spec3.03m Equilibrium: sum of resolved forces = 03.03t Coefficient of friction: F <= mu*R model3.03v Motion on rough surface: including inclined planes

In this question use \(g = 10 \text{ m s}^{-2}\). A particle of mass 3 kg rests in limiting equilibrium on a rough plane inclined at \(30°\) to the horizontal.
  1. Find the exact value of the coefficient of friction between the particle and the plane. [2]
A horizontal force of 36 N is now applied to the particle.
  1. Find how far down the plane the particle travels after the force has been applied for 4 s. [6]

In this question use $g = 10 \text{ m s}^{-2}$.

A particle of mass 3 kg rests in limiting equilibrium on a rough plane inclined at $30°$ to the horizontal.

\begin{enumerate}[label=(\alph*)]
\item Find the exact value of the coefficient of friction between the particle and the plane. [2]
\end{enumerate}

A horizontal force of 36 N is now applied to the particle.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find how far down the plane the particle travels after the force has been applied for 4 s. [6]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM Mechanics 2021 Q5 [8]}}