| Exam Board | SPS |
|---|---|
| Module | SPS SM Pure (SPS SM Pure) |
| Year | 2021 |
| Session | May |
| Marks | 3 |
| Topic | Modulus function |
| Type | Solve |linear| = |linear| (both linear inside) |
| Difficulty | Easy -1.2 This is a straightforward modulus equation requiring consideration of cases based on critical values x = 1/2 and x = -3. The solution involves basic algebraic manipulation after removing the modulus signs in each case, making it easier than average with no conceptual difficulty beyond understanding absolute value definition. |
| Spec | 1.02l Modulus function: notation, relations, equations and inequalities |
Solve the equation $|2x - 1| = |x + 3|$. [3]
\hfill \mbox{\textit{SPS SPS SM Pure 2021 Q2 [3]}}