SPS SPS FM 2021 March — Question 2 5 marks

Exam BoardSPS
ModuleSPS FM (SPS FM)
Year2021
SessionMarch
Marks5
TopicReciprocal Trig & Identities
TypeProve identity then solve equation
DifficultyStandard +0.3 Part (i) is a straightforward identity manipulation using tan²θ = sec²θ - 1 and 1/cosθ = secθ (routine recall). Part (ii) requires solving a quadratic in secθ and considering the range of secθ, which is standard A-level technique. The 5-mark total and multi-step nature elevate it slightly above trivial, but it remains easier than average with no novel insight required.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.05o Trigonometric equations: solve in given intervals

  1. Express \(2 \tan^2 \theta - \frac{1}{\cos \theta}\) in terms of \(\sec \theta\). [1]
  2. Hence solve, for \(0° < \theta < 360°\), the equation $$2 \tan^2 \theta - \frac{1}{\cos \theta} = 4.$$ [4]

\begin{enumerate}[label=(\roman*)]
\item Express $2 \tan^2 \theta - \frac{1}{\cos \theta}$ in terms of $\sec \theta$. [1]
\item Hence solve, for $0° < \theta < 360°$, the equation
$$2 \tan^2 \theta - \frac{1}{\cos \theta} = 4.$$ [4]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM 2021 Q2 [5]}}