WJEC Unit 3 2023 June — Question 11 7 marks

Exam BoardWJEC
ModuleUnit 3 (Unit 3)
Year2023
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStationary points and optimisation
TypeClassify nature of stationary points
DifficultyStandard +0.3 This is a straightforward calculus question requiring finding f''(x), solving f''(x)=0 for the inflection point, checking f'(x) at that point to determine if stationary, and using f''(x)<0 for concavity. All steps are routine differentiation and algebraic manipulation with no conceptual challenges, making it slightly easier than average.
Spec1.07e Second derivative: as rate of change of gradient1.07f Convexity/concavity: points of inflection1.07p Points of inflection: using second derivative

A curve C has equation \(f(x) = 5x^3 + 2x^2 - 3x\).
  1. Find the \(x\)-coordinate of the point of inflection. State, with a reason, whether the point of inflection is stationary or non-stationary. [5]
  2. Determine the range of values of \(x\) for which C is concave. [2]

A curve C has equation $f(x) = 5x^3 + 2x^2 - 3x$.

\begin{enumerate}[label=(\alph*)]
\item Find the $x$-coordinate of the point of inflection. State, with a reason, whether the point of inflection is stationary or non-stationary. [5]

\item Determine the range of values of $x$ for which C is concave. [2]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 3 2023 Q11 [7]}}