WJEC Unit 1 Specimen — Question 16 5 marks

Exam BoardWJEC
ModuleUnit 1 (Unit 1)
SessionSpecimen
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStationary points and optimisation
TypeFind range where function increasing/decreasing
DifficultyStandard +0.3 This is a standard calculus application requiring differentiation of a cubic, setting f'(x) > 0, and solving a quadratic inequality. While it involves multiple steps (differentiate, factorise/solve quadratic, determine sign), these are routine A-level techniques with no novel insight required, making it slightly easier than average.
Spec1.07o Increasing/decreasing: functions using sign of dy/dx

Find the range of values of \(x\) for which the function $$f(x) = x^3 - 5x^2 - 8x + 13$$ is an increasing function. [5]

AnswerMarks Guidance
\(f'(x) = 3x^2 – 10x – 8\)M1 AO1 (At least one non-zero term correct)
Critical values \(x = -\frac{2}{3}\), \(x = 4\)A1 AO1 (c.a.o.)
For an increasing function, \(f'(x) > 0\)m1 AO1
For an increasing function \(x < -\frac{2}{3}\) or \(x > 4\)A2 AO2 (f.t. candidate's derived two critical values for \(x\))
Deduct 1 mark for each of the following errors: the use of non-strict inequalities; the use of the word 'and' instead of the word 'or'
Total: [5]
$f'(x) = 3x^2 – 10x – 8$ | M1 | AO1 (At least one non-zero term correct)

Critical values $x = -\frac{2}{3}$, $x = 4$ | A1 | AO1 (c.a.o.)

For an increasing function, $f'(x) > 0$ | m1 | AO1

For an increasing function $x < -\frac{2}{3}$ or $x > 4$ | A2 | AO2 (f.t. candidate's derived two critical values for $x$)

Deduct 1 mark for each of the following errors: the use of non-strict inequalities; the use of the word 'and' instead of the word 'or' | — | —

**Total: [5]**

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Find the range of values of $x$ for which the function
$$f(x) = x^3 - 5x^2 - 8x + 13$$
is an increasing function. [5]

\hfill \mbox{\textit{WJEC Unit 1  Q16 [5]}}