WJEC Unit 1 2019 June — Question 09 12 marks

Exam BoardWJEC
ModuleUnit 1 (Unit 1)
Year2019
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircles
TypeCircle from diameter endpoints
DifficultyModerate -0.3 This is a straightforward coordinate geometry question testing standard circle and line intersection techniques. Part (a) is trivial midpoint calculation, part (b) requires expanding circle equation (routine), part (c) involves substituting a line into circle equation and solving a quadratic (standard procedure), and part (d) uses basic area formula. All steps are textbook exercises with no novel insight required, making it slightly easier than average.
Spec1.02q Use intersection points: of graphs to solve equations1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03e Complete the square: find centre and radius of circle

The points \(A(-2, 4)\) and \(B(6, 10)\) are such that \(AB\) is the diameter of a circle.
  1. Show that the centre of the circle has coordinates \((2, 7)\). [1]
  2. The equation of the circle is \(x^2 + y^2 + ax + by + c = 0\). Determine the values of \(a\), \(b\), \(c\). [3]
A straight line, with equation \(y = x + 6\), passes through the point \(A\) and cuts the circle again at the point \(C\).
  1. Find the coordinates of \(C\). [5]
  2. Calculate the exact area of the triangle \(ABC\). [3]

The points $A(-2, 4)$ and $B(6, 10)$ are such that $AB$ is the diameter of a circle.

\begin{enumerate}[label=(\alph*)]
\item Show that the centre of the circle has coordinates $(2, 7)$. [1]

\item The equation of the circle is $x^2 + y^2 + ax + by + c = 0$.
Determine the values of $a$, $b$, $c$. [3]
\end{enumerate}

A straight line, with equation $y = x + 6$, passes through the point $A$ and cuts the circle again at the point $C$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumii}{2}
\item Find the coordinates of $C$. [5]

\item Calculate the exact area of the triangle $ABC$. [3]
\end{enumerate}

\hfill \mbox{\textit{WJEC Unit 1 2019 Q09 [12]}}