| Exam Board | Edexcel |
|---|---|
| Module | AS Paper 1 (AS Paper 1) |
| Session | Specimen |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors Introduction & 2D |
| Type | Vector between two points |
| Difficulty | Easy -1.2 This is a straightforward two-part question testing basic vector operations: finding a displacement vector by subtraction and calculating its magnitude using Pythagoras. Both are routine procedures requiring only direct application of standard formulas with no problem-solving or insight needed. |
| Spec | 1.10c Magnitude and direction: of vectors1.10d Vector operations: addition and scalar multiplication |
| Answer | Marks | Guidance |
|---|---|---|
| 3(a) | Attempts AB(cid:32)OB(cid:16)OA or similar | M1 |
| AB(cid:32)5i(cid:14)10j | A1 | 1.1b |
| Answer | Marks | Guidance |
|---|---|---|
| (b) | Finds length using 'Pythagoras' AB (cid:32) (5)2 (cid:14)(10)2 | M1 |
| AB (cid:32)5 5 | A1ft | 1.1b |
| Answer | Marks | Guidance |
|---|---|---|
| Question | Scheme | Marks |
Question 3:
--- 3(a) ---
3(a) | Attempts AB(cid:32)OB(cid:16)OA or similar | M1 | 1.1b
AB(cid:32)5i(cid:14)10j | A1 | 1.1b
(2)
(b) | Finds length using 'Pythagoras' AB (cid:32) (5)2 (cid:14)(10)2 | M1 | 1.1b
AB (cid:32)5 5 | A1ft | 1.1b
(2)
(4 marks)
Notes:
(a)
M1: Attempts subtraction but may omit brackets
A1: cao (allow column vector notation)
(b)
M1: Correct use of Pythagoras theorem or modulus formula using their answer to (a)
A1ft: AB (cid:32)5 5 ft from their answer to (a)
Note that the correct answer implies M1A1 in each part of this question
Question | Scheme | Marks | AOsGiven that the point $A$ has position vector $3\mathbf{i} - 7\mathbf{j}$ and the point $B$ has position vector $8\mathbf{i} + 3\mathbf{j}$.
\begin{enumerate}[label=(\alph*)]
\item find the vector $\overrightarrow{AB}$
[2]
\item Find $|\overrightarrow{AB}|$. Give your answer as a simplified surd.
[2]
\end{enumerate}
\hfill \mbox{\textit{Edexcel AS Paper 1 Q3 [4]}}