Edexcel AEA 2002 June — Question 3 11 marks

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2002
SessionJune
Marks11
PaperDownload PDF ↗
TopicParametric curves and Cartesian conversion
TypeTangent/normal intersection problems
DifficultyChallenging +1.8 This question requires finding the normal at a given point on a parametric curve, then solving a system where this normal intersects the curve again. Students must: (1) find which t-value gives (14,1), (2) compute dy/dx using parametric differentiation, (3) find the normal equation, (4) substitute parametric equations into the normal to get a cubic in t, and (5) solve this cubic knowing one root. The multi-step nature, parametric context, and need to solve a cubic equation make this substantially harder than typical A-level questions, though it's more computational than conceptually deep for an AEA problem.
Spec1.03g Parametric equations: of curves and conversion to cartesian1.07m Tangents and normals: gradient and equations1.07s Parametric and implicit differentiation

The curve \(C\) has parametric equations $$x = 15t - t^3, \quad y = 3 - 2t^2.$$ Find the values of \(t\) at the points where the normal to \(C\) at \((14, 1)\) cuts \(C\) again. [11]

The curve $C$ has parametric equations
$$x = 15t - t^3, \quad y = 3 - 2t^2.$$

Find the values of $t$ at the points where the normal to $C$ at $(14, 1)$ cuts $C$ again.
[11]

\hfill \mbox{\textit{Edexcel AEA 2002 Q3 [11]}}