OCR FP3 2008 January — Question 8 13 marks

Exam BoardOCR
ModuleFP3 (Further Pure Mathematics 3)
Year2008
SessionJanuary
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGroups
TypeIsomorphism between groups
DifficultyChallenging +1.3 This is a Further Maths FP3 group theory question requiring identification of identity elements, isomorphism analysis, and a closure proof. While it involves abstract algebra (inherently harder than standard A-level), the tasks are mostly routine applications of group theory definitions: finding identities is straightforward, isomorphism checks involve comparing orders/structures (standard technique), and the closure proof for D requires algebraic manipulation of fractions but follows a predictable pattern. The question tests understanding rather than requiring deep insight, making it moderately above average difficulty.
Spec8.03c Group definition: recall and use, show structure is/isn't a group8.03l Isomorphism: determine using informal methods

Groups \(A\), \(B\), \(C\) and \(D\) are defined as follows: \(A\): the set of numbers \(\{2, 4, 6, 8\}\) under multiplication modulo 10, \(B\): the set of numbers \(\{1, 5, 7, 11\}\) under multiplication modulo 12, \(C\): the set of numbers \(\{2^0, 2^1, 2^2, 2^3\}\) under multiplication modulo 15, \(D\): the set of numbers \(\left\{\frac{1+2m}{1+2n}, \text{ where } m \text{ and } n \text{ are integers}\right\}\) under multiplication.
  1. Write down the identity element for each of groups \(A\), \(B\), \(C\) and \(D\). [2]
  2. Determine in each case whether the groups
    \(A\) and \(B\), \(B\) and \(C\), \(A\) and \(C\)
    are isomorphic or non-isomorphic. Give sufficient reasons for your answers. [5]
  3. Prove the closure property for group \(D\). [4]
  4. Elements of the set \(\left\{\frac{1+2m}{1+2n}, \text{ where } m \text{ and } n \text{ are integers}\right\}\) are combined under addition. State which of the four basic group properties are not satisfied. (Justification is not required.) [2]

(i)
Group A: \(e = 6\)
Group B: \(e = 1\)
Group C: \(e = 2^0\) OR \(1\)
Group D: \(e = 1\)
AnswerMarks
B1For any two correct identities
B1For two other correct identities
2AEF for D, but not "\(m = n\)"
(ii)
AnswerMarks
B1*For showing group table OR sufficient details of orders of elements OR stating cyclic / non-cyclic / Klein group (as appropriate)
B1*for one of groups A, B, C
B1*for another of groups A, B, C
\(A \not\cong B\)
\(B \not\cong C\)
\(A \cong C\)
AnswerMarks
B1 (dep*)For stating non-isomorphic with sufficient detail relating to the first 2 marks
B1 (dep*)For stating non-isomorphic
B1 (dep*)For stating isomorphic
5
(iii)
\(\frac{1+2m}{1+2n} \cdot \frac{1+2p}{1+2q} \cdot \frac{1+2m+2p+4mp}{1+2q+4nq}\)
AnswerMarks
M1*For considering product of 2 distinct elements of this form
M1 (dep*)For multiplying out
A1For simplifying to form shown
\(= \frac{1+2(m+p+2mp)}{1+2(n+q+2nq)} = \frac{1+2r}{1+2x}\)
AnswerMarks
A1For identifying as correct form, so closed (4 marks)
SR\(\frac{\text{odd}}{\text{odd}} \times \frac{\text{odd}}{\text{odd}} \times \frac{\text{odd}}{\text{odd}}\) earns full credit
SRIf clearly attempting to prove commutativity, allow at most M1
(iv)
Closure not satisfied
Identity and inverse not satisfied
AnswerMarks
B1For stating closure
B1For stating identity and inverse (2 marks)
SRIf associativity is stated as not satisfied then award at most B1 B0 OR B0 B1
## (i)

Group A: $e = 6$

Group B: $e = 1$

Group C: $e = 2^0$ OR $1$

Group D: $e = 1$

| B1 | For any two correct identities |
| B1 | For two other correct identities |
| 2 | AEF for D, but not "$m = n$" |

## (ii)

| B1* | For showing group table OR sufficient details of orders of elements OR stating cyclic / non-cyclic / Klein group (as appropriate) |
| B1* | for one of groups A, B, C |
| B1* | for another of groups A, B, C |

$A \not\cong B$

$B \not\cong C$

$A \cong C$

| B1 (dep*) | For stating non-isomorphic with sufficient detail relating to the first 2 marks |
| B1 (dep*) | For stating non-isomorphic |
| B1 (dep*) | For stating isomorphic |
| 5 | |

## (iii)

$\frac{1+2m}{1+2n} \cdot \frac{1+2p}{1+2q} \cdot \frac{1+2m+2p+4mp}{1+2q+4nq}$

| M1* | For considering product of 2 distinct elements of this form |
| M1 (dep*) | For multiplying out |
| A1 | For simplifying to form shown |

$= \frac{1+2(m+p+2mp)}{1+2(n+q+2nq)} = \frac{1+2r}{1+2x}$

| A1 | For identifying as correct form, so closed (4 marks) |

| SR | $\frac{\text{odd}}{\text{odd}} \times \frac{\text{odd}}{\text{odd}} \times \frac{\text{odd}}{\text{odd}}$ earns full credit |
| SR | If clearly attempting to prove commutativity, allow at most M1 |

## (iv)

Closure not satisfied

Identity and inverse not satisfied

| B1 | For stating closure |
| B1 | For stating identity and inverse (2 marks) |

| SR | If associativity is stated as not satisfied then award at most B1 B0 OR B0 B1 |
Groups $A$, $B$, $C$ and $D$ are defined as follows:

$A$: the set of numbers $\{2, 4, 6, 8\}$ under multiplication modulo 10,

$B$: the set of numbers $\{1, 5, 7, 11\}$ under multiplication modulo 12,

$C$: the set of numbers $\{2^0, 2^1, 2^2, 2^3\}$ under multiplication modulo 15,

$D$: the set of numbers $\left\{\frac{1+2m}{1+2n}, \text{ where } m \text{ and } n \text{ are integers}\right\}$ under multiplication.

\begin{enumerate}[label=(\roman*)]
\item Write down the identity element for each of groups $A$, $B$, $C$ and $D$. [2]

\item Determine in each case whether the groups
\begin{center}
$A$ and $B$,\\
$B$ and $C$,\\
$A$ and $C$
\end{center}
are isomorphic or non-isomorphic. Give sufficient reasons for your answers. [5]

\item Prove the closure property for group $D$. [4]

\item Elements of the set $\left\{\frac{1+2m}{1+2n}, \text{ where } m \text{ and } n \text{ are integers}\right\}$ are combined under addition. State which of the four basic group properties are not satisfied. (Justification is not required.) [2]
\end{enumerate}

\hfill \mbox{\textit{OCR FP3 2008 Q8 [13]}}