OCR FP3 — Question 5 9 marks

Exam BoardOCR
ModuleFP3 (Further Pure Mathematics 3)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeSubstitution reducing to first order linear ODE
DifficultyStandard +0.8 This is a Further Pure 3 differential equations question requiring a non-obvious substitution (given) followed by solving a separable equation and back-substitution. While the substitution is provided, students must carefully apply the chain rule and algebraic manipulation (4 marks), then solve the resulting separable DE and express the final answer correctly (5 marks). The multi-step nature, algebraic complexity, and FP3 context place this moderately above average difficulty.
Spec1.08k Separable differential equations: dy/dx = f(x)g(y)4.10c Integrating factor: first order equations

The variables \(x\) and \(y\) are related by the differential equation $$x^3 \frac{dy}{dx} = xy + x + 1. \qquad (A)$$
  1. Use the substitution \(y = u - \frac{1}{x}\), where \(u\) is a function of \(x\), to show that the differential equation may be written as $$x^2 \frac{du}{dx} = u.$$ [4]
  2. Hence find the general solution of the differential equation (A), giving your answer in the form \(y = f(x)\). [5]

The variables $x$ and $y$ are related by the differential equation
$$x^3 \frac{dy}{dx} = xy + x + 1. \qquad (A)$$

\begin{enumerate}[label=(\roman*)]
\item Use the substitution $y = u - \frac{1}{x}$, where $u$ is a function of $x$, to show that the differential equation may be written as
$$x^2 \frac{du}{dx} = u.$$ [4]
\item Hence find the general solution of the differential equation (A), giving your answer in the form $y = f(x)$. [5]
\end{enumerate}

\hfill \mbox{\textit{OCR FP3  Q5 [9]}}