OCR FP2 2012 January — Question 4 9 marks

Exam BoardOCR
ModuleFP2 (Further Pure Mathematics 2)
Year2012
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAreas by integration
TypeBounds using rectangles
DifficultyStandard +0.8 This FP2 question on numerical integration requires understanding Riemann sums with a non-standard function (e^(-1/x)) and involves multiple conceptual steps: explaining the lower bound structure, constructing an upper bound, numerical evaluation, and finding N by analyzing the difference between bounds. The final part requires algebraic manipulation of exponential series and solving an inequality, which is more demanding than routine integration questions but remains within standard FP2 scope.
Spec1.09f Trapezium rule: numerical integration

\includegraphics{figure_4} The diagram shows the curve \(y = e^{-\frac{1}{x}}\) for \(0 < x \leq 1\). A set of \((n - 1)\) rectangles is drawn under the curve as shown.
  1. Explain why a lower bound for \(\int_0^1 e^{-\frac{1}{x}} dx\) can be expressed as $$\frac{1}{n}\left(e^{-n} + e^{-\frac{n}{2}} + e^{-\frac{n}{3}} + \ldots + e^{-\frac{n}{n-1}}\right).$$ [2]
  2. Using a set of \(n\) rectangles, write down a similar expression for an upper bound for \(\int_0^1 e^{-\frac{1}{x}} dx\). [2]
  3. Evaluate these bounds in the case \(n = 4\), giving your answers correct to 3 significant figures. [2]
  4. When \(n > N\), the difference between the upper and lower bounds is less than 0.001. By expressing this difference in terms of \(n\), find the least possible value of \(N\). [3]

(i)
AnswerMarks Guidance
Given expression is sum of areas of rectangles of width \(\frac{1}{n}\), heights \(e^{-1/x}\)B1 For identifying rectangle widths and heights
Given integral is area under the curve which is clearly greaterB1 For correct explanation of lower bound
[2]
(ii)
AnswerMarks Guidance
Upper bound \(= \frac{1}{n}\left(e^{-n} + e^{-\frac{n}{2}} + e^{-\frac{n}{3}} + \ldots + e^{-\frac{n}{n-1}} + e^{-1}\right)\)M1 A1 For using n upper rectangles soi by \(e^{-n}\) and \(e^{-1}\); For correct expression
[2]
(iii)
AnswerMarks Guidance
Lower bound = 0.104(31)B1 For correct value
Upper bound = 0.196(28)B1 For correct value – accept 0.197
[2]
(iv)
AnswerMarks Guidance
\(\frac{1}{n}e^{-1} < 0.001\)B1 For a correct statement (includes <)
\(\Rightarrow n > \frac{1000}{e} = 367.879\)M1 For rearranging (ignore < > = and allow RHS = \(10^{\ell/m} e^{\pm 1}\))
\(\Rightarrow\) least N = 368A1 For correct value
[3]
### (i)

Given expression is sum of areas of rectangles of width $\frac{1}{n}$, heights $e^{-1/x}$ | B1 | For identifying rectangle widths and heights

Given integral is area under the curve which is clearly greater | B1 | For correct explanation of lower bound

| [2] |

### (ii)

Upper bound $= \frac{1}{n}\left(e^{-n} + e^{-\frac{n}{2}} + e^{-\frac{n}{3}} + \ldots + e^{-\frac{n}{n-1}} + e^{-1}\right)$ | M1 A1 | For using n upper rectangles soi by $e^{-n}$ and $e^{-1}$; For correct expression

| [2] |

### (iii)

Lower bound = 0.104(31) | B1 | For correct value

Upper bound = 0.196(28) | B1 | For correct value – accept 0.197

| [2] |

### (iv)

$\frac{1}{n}e^{-1} < 0.001$ | B1 | For a correct statement (includes <)

$\Rightarrow n > \frac{1000}{e} = 367.879$ | M1 | For rearranging (ignore < > = and allow RHS = $10^{\ell/m} e^{\pm 1}$)

$\Rightarrow$ least N = 368 | A1 | For correct value

| [3] |

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\includegraphics{figure_4}

The diagram shows the curve $y = e^{-\frac{1}{x}}$ for $0 < x \leq 1$. A set of $(n - 1)$ rectangles is drawn under the curve as shown.

\begin{enumerate}[label=(\roman*)]
\item Explain why a lower bound for $\int_0^1 e^{-\frac{1}{x}} dx$ can be expressed as
$$\frac{1}{n}\left(e^{-n} + e^{-\frac{n}{2}} + e^{-\frac{n}{3}} + \ldots + e^{-\frac{n}{n-1}}\right).$$ [2]

\item Using a set of $n$ rectangles, write down a similar expression for an upper bound for $\int_0^1 e^{-\frac{1}{x}} dx$. [2]

\item Evaluate these bounds in the case $n = 4$, giving your answers correct to 3 significant figures. [2]

\item When $n > N$, the difference between the upper and lower bounds is less than 0.001. By expressing this difference in terms of $n$, find the least possible value of $N$. [3]
\end{enumerate}

\hfill \mbox{\textit{OCR FP2 2012 Q4 [9]}}