Edexcel M5 — Question 6 19 marks

Exam BoardEdexcel
ModuleM5 (Mechanics 5)
Marks19
PaperDownload PDF ↗
TopicCircular Motion 2
TypeAngular speed and period
DifficultyChallenging +1.8 This is a challenging M5 compound pendulum problem requiring moment of inertia calculations using parallel axis theorem for composite bodies, energy methods to find angular velocity, force analysis in rotating frames, and small angle SHM approximation. The multi-component setup (rod + lamina) and the need to resolve forces along AB while accounting for centripetal effects makes this substantially harder than standard pendulum questions, though the structured parts guide the solution.
Spec6.02i Conservation of energy: mechanical energy principle6.04b Find centre of mass: using symmetry6.05e Radial/tangential acceleration

A pendulum consists of a uniform rod \(AB\), of length \(4a\) and mass \(2m\), whose end \(A\) is rigidly attached to the centre \(O\) of a uniform square lamina \(PQRS\), of mass \(4m\) and side \(a\). The rod \(AB\) is perpendicular to the plane of the lamina. The pendulum is free to rotate about a fixed smooth horizontal axis \(L\) which passes through \(B\). The axis \(L\) is perpendicular to \(AB\) and parallel to the edge \(PQ\) of the square.
  1. Show that the moment of inertia of the pendulum about \(L\) is \(75ma^2\). [4]
The pendulum is released from rest when \(BA\) makes an angle \(\alpha\) with the downward vertical through \(B\), where \(\tan \alpha = \frac{3}{4}\). When \(BA\) makes an angle \(\theta\) with the downward vertical through \(B\), the magnitude of the component, in the direction \(AB\), of the force exerted by the axis \(L\) on the pendulum is \(X\).
  1. Find an expression for \(X\) in terms of \(m\), \(g\) and \(\theta\). [9]
Using the approximation \(\theta \approx \sin \theta\),
  1. find an estimate of the time for the pendulum to rotate through an angle \(\alpha\) from its initial rest position. [6]

A pendulum consists of a uniform rod $AB$, of length $4a$ and mass $2m$, whose end $A$ is rigidly attached to the centre $O$ of a uniform square lamina $PQRS$, of mass $4m$ and side $a$. The rod $AB$ is perpendicular to the plane of the lamina. The pendulum is free to rotate about a fixed smooth horizontal axis $L$ which passes through $B$. The axis $L$ is perpendicular to $AB$ and parallel to the edge $PQ$ of the square.

\begin{enumerate}[label=(\alph*)]
\item Show that the moment of inertia of the pendulum about $L$ is $75ma^2$.
[4]
\end{enumerate}

The pendulum is released from rest when $BA$ makes an angle $\alpha$ with the downward vertical through $B$, where $\tan \alpha = \frac{3}{4}$. When $BA$ makes an angle $\theta$ with the downward vertical through $B$, the magnitude of the component, in the direction $AB$, of the force exerted by the axis $L$ on the pendulum is $X$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find an expression for $X$ in terms of $m$, $g$ and $\theta$.
[9]
\end{enumerate}

Using the approximation $\theta \approx \sin \theta$,

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item find an estimate of the time for the pendulum to rotate through an angle $\alpha$ from its initial rest position.
[6]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M5  Q6 [19]}}