Edexcel M4 2013 June — Question 1 13 marks

Exam BoardEdexcel
ModuleM4 (Mechanics 4)
Year2013
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable Force
TypeAir resistance kv - vertical motion
DifficultyStandard +0.8 This is a standard M4 resisting forces question requiring formation and solution of a differential equation (Newton's second law with air resistance), followed by integration to find distance. While it involves multiple steps and exponential functions, it follows a well-established method taught explicitly in M4. The 8+5 mark allocation and 'show that' format indicate moderate difficulty, but this is routine for Further Maths mechanics students who have practiced this exact type of problem.
Spec1.08d Evaluate definite integrals: between limits3.03r Friction: concept and vector form6.06a Variable force: dv/dt or v*dv/dx methods

A particle \(P\) of mass \(0.5\) kg falls vertically from rest. After \(t\) seconds it has speed \(v\) m s\(^{-1}\). A resisting force of magnitude \(1.5v\) newtons acts on \(P\) as it falls.
  1. Show that \(3v = 9.8(1 - e^{-3t})\). [8]
  2. Find the distance that \(P\) falls in the first two seconds of its motion. [5]

Question 1:
1
Question 1:
1
A particle $P$ of mass $0.5$ kg falls vertically from rest. After $t$ seconds it has speed $v$ m s$^{-1}$. A resisting force of magnitude $1.5v$ newtons acts on $P$ as it falls.

\begin{enumerate}[label=(\alph*)]
\item Show that $3v = 9.8(1 - e^{-3t})$.
[8]

\item Find the distance that $P$ falls in the first two seconds of its motion.
[5]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M4 2013 Q1 [13]}}