Edexcel M3 — Question 3 10 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMotion on a slope
TypeMotion down smooth slope
DifficultyChallenging +1.2 This is a standard M3 banked curve problem requiring resolution of forces in two directions and application of circular motion principles. While it involves multiple steps (resolving perpendicular and parallel to the plane, using F=mv²/r, algebraic manipulation with the given condition), the approach is methodical and follows established techniques taught in M3. The 10 marks reflect the working required rather than conceptual difficulty. It's harder than routine mechanics questions but doesn't require novel insight—students who've practiced banked curve problems will recognize the standard method.
Spec6.05c Horizontal circles: conical pendulum, banked tracks

A car of mass \(m\) kg moves round a curve of radius \(r\) m on a road which is banked at an angle \(\theta\) to the horizontal. When the speed of the car is \(u\) ms\(^{-1}\), the car experiences no sideways frictional force. Given that \(\tan \theta = \frac{u^2}{gr}\), show that the sideways frictional force on the car when its speed is \(\frac{u}{2}\) ms\(^{-1}\) has magnitude \(\frac{3}{4}mg \sin \theta\) N. [10 marks]

AnswerMarks
Speed \(< u\), so friction \(F\) acts up. \(R \cos \theta + F \sin \theta = mg\) (1)B1 M1 A1
\(R \sin \theta - F \cos \theta = \frac{mu^2}{4r}\) (2)M1 A1 A1 M1
(1) \(\times \sin \theta\), (2) \(\times \cos \theta\), subtract:
\(F = mg \sin \theta - \frac{mu^2}{4r}\cos \theta = mg \sin \theta - \frac{u^2}{4}\tan \theta \cos \theta = \frac{3}{4}mg \sin \theta\)A1 A1 A1
Total: 10 marks
Speed $< u$, so friction $F$ acts up. $R \cos \theta + F \sin \theta = mg$ (1) | B1 M1 A1 |

$R \sin \theta - F \cos \theta = \frac{mu^2}{4r}$ (2) | M1 A1 A1 M1 |

(1) $\times \sin \theta$, (2) $\times \cos \theta$, subtract: | |

$F = mg \sin \theta - \frac{mu^2}{4r}\cos \theta = mg \sin \theta - \frac{u^2}{4}\tan \theta \cos \theta = \frac{3}{4}mg \sin \theta$ | A1 A1 A1 |

**Total: 10 marks**

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A car of mass $m$ kg moves round a curve of radius $r$ m on a road which is banked at an angle $\theta$ to the horizontal. When the speed of the car is $u$ ms$^{-1}$, the car experiences no sideways frictional force. Given that $\tan \theta = \frac{u^2}{gr}$, show that the sideways frictional force on the car when its speed is $\frac{u}{2}$ ms$^{-1}$ has magnitude $\frac{3}{4}mg \sin \theta$ N. [10 marks]

\hfill \mbox{\textit{Edexcel M3  Q3 [10]}}